Nursing Elites

1. What is the 'lock-and-key' model?

• A. Protein folding
• B. Enzyme-substrate interaction
• C. Muscle contraction
• D. Blood clotting

Correct answer: B

Rationale: The 'lock-and-key' model describes the specificity of the interaction between enzymes and their substrates. In this model, the enzyme's active site acts like a lock that can only be opened by the specific substrate molecule, which serves as the key. This specific binding ensures that enzymes catalyze particular reactions and do not interact with other molecules indiscriminately. Protein folding (option A) is the process by which a protein attains its functional three-dimensional structure but is not directly related to the lock-and-key model. Muscle contraction (option C) and blood clotting (option D) are complex biological processes but are not directly associated with the lock-and-key model of enzyme-substrate interaction.

2. What is the name of the long bone found in the upper arm?

• A. Femur
• B. Tibia
• C. Humerus
• D. Radius

Correct answer: C

Rationale: The correct answer is the humerus. The humerus is the long bone located in the upper arm, between the shoulder and elbow. Option A, Femur, is incorrect as it is the long bone found in the thigh. Option B, Tibia, is incorrect as it is a long bone found in the lower leg. Option D, Radius, is incorrect as it is a bone located in the forearm, not the upper arm.

3. Why are noble gas elements generally unreactive?

• A. They are too large and cannot form bonds easily.
• B. They lack valence electrons in their outermost shell.
• C. They have strong bonds within their own molecules.
• D. They have already achieved stable electron configurations.

Correct answer: D

Rationale: The correct answer is D. Noble gas elements are generally unreactive because they have already achieved stable electron configurations by having a full outer electron shell. This full shell makes them very stable and unlikely to gain, lose, or share electrons with other elements. Choices A, B, and C are incorrect because noble gases are not unreactive due to being too large to form bonds easily (A), lacking valence electrons in their outermost shell (B), or having strong bonds within their own molecules (C).

4. What is the end result of mitosis in animal cells?

• A. The production of two identical daughter cells
• B. The production of four haploid cells
• C. The production of a single diploid cell
• D. The production of a single haploid cell

Correct answer: A

Rationale: Mitosis is a type of cell division specific to eukaryotic cells that results in the production of two identical daughter cells, each with the same genetic material as the parent cell. This process is crucial for growth, tissue repair, and maintaining a constant number of chromosomes in multicellular organisms. During mitosis, the replicated chromosomes are segregated into two separate nuclei, followed by the division of the cell into two identical daughter cells. Options B, C, and D are incorrect as mitosis does not lead to the production of four haploid cells, a single diploid cell, or a single haploid cell. The correct answer is A because mitosis results in the formation of two daughter cells that are genetically identical to each other and to the parent cell, allowing for growth and replacement of damaged cells in multicellular organisms.

5. Which compound is a component of baking soda and is important for maintaining pH balance in the body?

• A. Potassium
• B. Sodium
• C. Calcium
• D. Sodium bicarbonate

Correct answer: D

Rationale: The correct answer is D, Sodium bicarbonate. Sodium bicarbonate, commonly known as baking soda, is a compound that plays a crucial role in maintaining pH balance in the body. When ingested, sodium bicarbonate acts as a buffer, helping to regulate the body's pH levels. It is essential for various physiological functions. Choices A, B, and C are incorrect. Potassium, calcium, and sodium are important minerals in the body but are not components of baking soda or directly responsible for maintaining pH balance in the same way as sodium bicarbonate.

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