the brain is part of the

ATI TEAS 7

ATI TEAS Science Test

1. The brain is part of which system?

A. Integumentary system
B. Nervous system
C. Endocrine system
D. Respiratory system

Correct answer: B

Rationale: The brain is a crucial organ that serves as the command center of the body, making it a key component of the nervous system. It processes sensory information, coordinates movements, and regulates various bodily functions. Therefore, the brain is correctly categorized as part of the nervous system. Choices A, C, and D are incorrect because the integumentary system pertains to the skin, the endocrine system involves hormone regulation, and the respiratory system is responsible for breathing. These systems do not encompass the brain's functions or structure.

2. Which of the following is NOT a recognized mode of natural selection?

A. Directional selection (favoring one extreme trait value on a spectrum)
B. Disruptive selection (favoring both extreme trait values on a spectrum)
C. Stabilizing selection (favoring the average trait value on a spectrum)
D. Sexual selection (selection based on mate choice that influences reproductive success)

Correct answer: D

Rationale: A) Directional selection is a recognized mode of natural selection where one extreme trait value on a spectrum is favored over others, leading to a shift in the average trait value over time. B) Disruptive selection is a recognized mode of natural selection where both extreme trait values on a spectrum are favored over the average trait value, potentially causing the population to split into distinct groups. C) Stabilizing selection is a recognized mode of natural selection favoring the average trait value on a spectrum over extreme values, resulting in reduced genetic diversity. D) Sexual selection differs from traditional natural selection modes as it involves mate choice and competition for mates, not direct selection pressure on traits affecting survival and reproduction in the environment. Sexual selection can drive the evolution of traits enhancing an individual's attractiveness for mating purposes.

3. Which term describes the resistance of a substance to being hammered into different shapes?

A. Viscosity
B. Ductility
C. Malleability
D. Conductivity

Correct answer: C

Rationale: Malleability is the property that allows a substance to be hammered or rolled into thin sheets without breaking. It is the opposite of brittleness. Ductility refers to the ability of a material to be drawn into thin wires, not hammered into shapes. Viscosity is the measure of a fluid's resistance to flow, indicating how thick or sticky it is, not related to shaping by hammering. Conductivity refers to the ability of a material to conduct electricity or heat, not resistance to being hammered into different shapes.

4. In the process of cellular respiration, glucose is broken down to produce energy. What is the main waste product released?

A. Water
B. Carbon dioxide
C. Oxygen
D. Protein

Correct answer: B

Rationale: During cellular respiration, glucose undergoes a series of reactions in the presence of oxygen to produce energy in the form of ATP. The main waste product released in this process is carbon dioxide, which is eliminated from the body through exhalation. While water is also produced as a byproduct of cellular respiration, carbon dioxide is considered the primary waste product. Oxygen is not a waste product but is actually consumed during cellular respiration to aid in breaking down glucose. Protein is essential for various cellular functions but is not a waste product of cellular respiration; instead, proteins are broken down into amino acids for cellular processes.

5. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?

A. 31.25 mL
B. 32 mL
C. 30 mL
D. 31.3 mL

Correct answer: B

Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.