how many molecules of nadph and atp are required to reduce 6 molecules of co2 to glucose via photosynthesis
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ATI TEAS 7

Practice TEAS Science Test

1. How many molecules of NADPH and ATP are required to reduce 6 molecules of CO2 to glucose via photosynthesis?

Correct answer: B

Rationale: During photosynthesis, 12 molecules of NADPH and 18 molecules of ATP are required to reduce 6 molecules of CO2 to glucose. NADPH and ATP are essential energy carriers in the process of photosynthesis. Choice A is incorrect because it underestimates the required molecules of both NADPH and ATP. Choices C and D overestimate the number of molecules needed, making them incorrect answers.

2. What is the difference between active and passive immunity?

Correct answer: B

Rationale: Active immunity involves the body's own immune response, where the individual's immune system produces antibodies in response to exposure to a pathogen or vaccine. This type of immunity is long-lasting because the immune system 'remembers' the pathogen and can mount a rapid response upon re-exposure. In contrast, passive immunity provides immediate protection through the transfer of pre-formed antibodies from another source, such as through maternal antibodies crossing the placenta or receiving antibodies through an injection. Passive immunity is short-lived because the transferred antibodies eventually degrade and are not produced by the recipient's immune system. Choice A is incorrect because active immunity is generally long-lasting, as it involves the production of antibodies by the individual's immune system. Choice C is incorrect as both active and passive immunity can work against various pathogens, not limited to bacteria or viruses. Choice D is incorrect as passive immunity does not require repeated vaccinations but provides temporary protection through the transfer of antibodies from an external source.

3. Which of the following hormones is primarily responsible for regulating metabolism?

Correct answer: D

Rationale: Thyroid hormone is the correct answer as it is primarily responsible for regulating metabolism. It plays a crucial role in controlling the body's metabolic rate, affecting how the body uses energy from food. Thyroid hormone levels can influence metabolism, energy production, and body weight regulation. Insulin, choice A, is involved in regulating blood sugar levels, not directly metabolism. Testosterone, choice B, is a sex hormone that primarily affects the development of male reproductive tissues. Adrenaline, choice C, is involved in the fight-or-flight response and not primarily responsible for regulating metabolism.

4. Which type of epithelial tissue lines the inner lining of your intestines, responsible for absorption?

Correct answer: B

Rationale: The correct answer is simple columnar epithelium. This type of epithelial tissue is well-suited for absorption and secretion due to its tall, column-like shape and the presence of microvilli on its surface, which increase the surface area for absorption in organs like the intestines. Simple columnar epithelium is the ideal choice for the inner lining of the intestines as it allows for efficient nutrient absorption. Stratified squamous epithelium is typically found in areas subjected to abrasion, like the skin, and not suited for absorption. Stratified cuboidal epithelium is rare and found in specific gland ducts, not in the intestines. Transitional epithelium is specialized for stretching and is primarily found in the urinary system, not involved in absorption processes in the intestines.

5. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?

Correct answer: B

Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.

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