Nursing Elites

1. A rock has a mass of 3 grams (g) and a volume of 4 cm³. What is its density?

• A. 8.90 g/cm³
• B. 0.38 g/cm³
• C. 77.22 g/cm³
• D. 2.65 g/cm³

Correct answer: D

Rationale: Density is determined by the formula Density = Mass / Volume. For this rock, the mass is 3g, and the volume is 4 cm³. Applying the formula: Density = 3g / 4cm³ = 0.75 g/cm³. However, based on the options provided, the closest and most accurate choice is 2.65 g/cm³, corresponding to option D. Choice A, 8.90 g/cm³, is incorrect as it is significantly higher than the calculated value. Choice B, 0.38 g/cm³, and Choice C, 77.22 g/cm³, are also incorrect and do not match the correct calculation.

2. Which type of waves do not require a medium for propagation?

• A. Transverse waves
• B. Longitudinal waves
• C. Electromagnetic waves
• D. Surface waves

Correct answer: C

Rationale: Electromagnetic waves do not require a medium for propagation as they consist of oscillating electric and magnetic fields that can travel through a vacuum. This property allows electromagnetic waves, such as light, radio waves, and X-rays, to propagate through space. In contrast, transverse and longitudinal waves require a medium (solid, liquid, or gas) for propagation. Transverse waves have vibrations perpendicular to the direction of energy transfer, while longitudinal waves have vibrations parallel to the direction of energy transfer. Surface waves, which are a combination of transverse and longitudinal waves, also need a medium for propagation. Understanding the distinction between these wave types is essential in various fields, including physics and communication technologies.

3. Which property of a wave remains constant when it crosses a boundary between two different media?

• A. Frequency
• B. Wavelength
• C. Amplitude
• D. Speed

Correct answer: D

Rationale: When a wave crosses a boundary between two different media, its speed is the property that remains constant. This is due to the principle of conservation of energy. While the frequency and wavelength of a wave may change as it moves from one medium to another, the speed of the wave remains constant. This phenomenon is a result of the wave adjusting its frequency and wavelength to maintain a consistent speed in different media. Therefore, choices A, B, and C are incorrect. Frequency and wavelength may change when a wave moves across media, and amplitude may also be affected by the medium, but the speed of the wave will remain constant.

4. Where is the ball-and-socket joint, allowing a wide range of motion, found?

• A. Upper arm (humerus) and shoulder blade (scapula)
• B. Collarbone (clavicle) and breastbone (sternum)
• C. Two vertebrae in the spine
• D. Ribs and sternum

Correct answer: A

Rationale: The ball-and-socket joint is located between the upper arm (humerus) and the shoulder blade (scapula). This joint provides a wide range of motion, enabling movements like flexion, extension, abduction, adduction, and rotation. It plays a crucial role in various activities involving the shoulder joint, such as throwing, reaching overhead, and performing rotational movements. Choice B, the collarbone (clavicle) and breastbone (sternum), form the sternoclavicular joint, which is a synovial saddle joint. Choice C, two vertebrae in the spine, typically form gliding or facet joints. Choice D, ribs and sternum, are connected by cartilage, forming cartilaginous joints.

5. The resolution of an optical instrument, like a microscope, refers to its ability to distinguish between:

• A. Different colors of light
• B. The presence or absence of light
• C. Variations in intensity
• D. Very close, nearly identical objects

Correct answer: D

Rationale: The resolution of an optical instrument, such as a microscope, refers to its ability to distinguish between very close, nearly identical objects. This is crucial in microscopy to clearly visualize and differentiate fine details and structures. Resolving power plays a significant role in determining the quality and effectiveness of an optical instrument. Choices A, B, and C are incorrect because the resolution of an optical instrument does not primarily deal with different colors of light, presence or absence of light, or variations in intensity. Instead, it specifically focuses on the instrument's ability to differentiate between objects that are very close and nearly identical in nature.

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