ATI TEAS 7
TEAS 7 practice test science
1. According to Newton's third law of motion, for every action, there is an equal and opposite _________.
- A. Reaction
- B. Force
- C. Acceleration
- D. Momentum
Correct answer: A
Rationale: Newton's third law of motion states that for every action, there is an equal and opposite reaction. This law emphasizes that forces always exist in pairs. When one object exerts a force on a second object (action), the second object exerts an equal force in the opposite direction back on the first object (reaction). This principle is crucial in understanding the interactions between objects and the resulting motion observed in the physical world. Choices B, C, and D are incorrect because while force is involved, the specific concept highlighted by Newton's third law is the equal and opposite reaction. Acceleration and momentum are also related to motion but are not directly tied to Newton's third law of motion, which focuses on the equality and oppositeness of forces in interactions.
2. What is the length of DNA that can code for a particular protein?
- A. Chromosome
- B. Nucleotide
- C. Gene
- D. Ribosome
Correct answer: C
Rationale: The correct answer is C: Gene. A gene is a specific segment of DNA that contains the information necessary to produce a particular protein. Genes are responsible for coding proteins, and each gene carries the instructions for a specific protein. Chromosomes consist of many genes and are not a specific length that codes for a protein. Nucleotides are the building blocks of DNA and are not a length that codes for a protein. Ribosomes are cellular organelles involved in protein synthesis and do not directly code for proteins.
3. Which of the following is an example of a nonpolar solvent?
- A. Water
- B. Ethanol
- C. Acetone
- D. Hydrochloric acid
Correct answer: B
Rationale: - Water (option A) is a polar solvent due to its uneven distribution of charge, with the oxygen atom being partially negative and the hydrogen atoms being partially positive. - Ethanol (option B) is a nonpolar solvent because it has a symmetrical molecular structure that does not result in significant charge separation. - Acetone (option C) is a polar solvent as it contains a carbonyl group that results in a partial negative charge on the oxygen atom. - Hydrochloric acid (option D) is a polar solvent due to the presence of the highly electronegative chlorine atom, which results in a partial negative charge.
4. How does an increase in temperature generally affect the solubility of most solid solutes in a liquid solvent?
- A. It increases solubility
- B. It decreases solubility
- C. It has no effect on solubility
- D. It depends on the nature of the solute
Correct answer: A
Rationale: In general, increasing temperature tends to increase the solubility of most solid solutes in liquid solvents. This occurs because higher temperatures provide more energy for the solvent molecules to break the solute-solvent attractive forces and allow more solute to dissolve. The increase in temperature facilitates the dissolution process by overcoming the intermolecular forces that hold the solute particles together. Choice B is incorrect because higher temperatures typically lead to greater solubility. Choice C is incorrect as temperature changes usually impact solubility. Choice D is incorrect because although the nature of the solute can influence solubility, the general trend is that higher temperatures enhance solubility for most solid solutes in liquid solvents.
5. What is the molarity of a solution made by dissolving 4.0 grams of NaCl into enough water to make 120 mL of solution? The atomic mass of Na is 23.0 g/mol, and Cl is 35.5 g/mol.
- A. 0.34 M
- B. 0.57 M
- C. 0.034 M
- D. 0.057 M
Correct answer: B
Rationale: To find the molarity, first calculate the moles of NaCl. Moles of NaCl = 4.0 g / (23.0 g/mol + 35.5 g/mol) = 0.068 mol. Next, use the formula for molarity: Molarity = moles of solute / liters of solution. Molarity = 0.068 mol / 0.120 L = 0.57 M. Therefore, the molarity of the solution is 0.57 M. Choice A, 0.34 M, is incorrect as it does not match the calculated molarity. Choice C, 0.034 M, is incorrect as it is a decimal point off from the correct molarity. Choice D, 0.057 M, is incorrect as it does not match the calculated molarity of 0.57 M.
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