Nursing Elites

1. A taxi service charges $50 for the first mile, $50 for each additional mile, and 20¢ per minute of waiting time. Joan took a cab from her place to a flower shop 8 miles away, where she bought a bouquet, then another 6 miles to her mother's place. The driver had to wait 9 minutes while she bought the bouquet. What was the fare?

• A. $650
• B. $710
• C. $701.80
• D. $650

Correct answer: C

Rationale: To calculate the fare, first, determine the cost for the distance traveled. Joan traveled a total of 14 miles (8 miles to the flower shop + 6 miles to her mother's place). The first mile costs $50, and the remaining 13 miles cost $50 each, totaling $700 for the distance. Additionally, the driver waited for 9 minutes, which incurs an additional cost of $1.80 (9 minutes x $0.20 per minute). Therefore, the total fare is calculated as: Cost for distance + Cost for waiting time = $50 + $650 + $1.80 = $701.80. Choice A, $650, is incorrect as it does not consider the waiting time cost. Choice B, $710, is incorrect as it does not accurately calculate the total fare. Choice D, $650, is incorrect for the same reason as Choice A. The correct total fare is $701.80.

2. A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?

• A. 24
• B. 28
• C. 36
• D. 38

Correct answer: C

Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.

3. Dr. Lee observed that 30% of all his patients developed an infection after taking a certain antibiotic. He further noticed that 5% of those 30% required hospitalization to recover from the infection. What percentage of Dr. Lee's patients were hospitalized after taking the antibiotic?

• A. 1.50%
• B. 5%
• C. 15%
• D. 30%

Correct answer: C

Rationale: Out of all the patients who took the antibiotic, 30% developed an infection. Among those with infections, 5% required hospitalization. To find the percentage of all patients hospitalized, we multiply the two percentages: 30% * 5% = 1.5%. Therefore, 1.5% of all patients were hospitalized. Choice A (1.50%) is the calculated percentage of all patients hospitalized, not 1.50%. Choice B (5%) is the percentage of patients who developed an infection and required hospitalization, not all patients. Choice D (30%) represents the initial percentage of patients who developed an infection, not the percentage hospitalized.

4. Gordon purchased a television that was 30% off its original price of $472. What was the sale price?

• A. 141.60
• B. 225.70
• C. 305.30
• D. 330.40

Correct answer: D

Rationale: To find the sale price after a 30% discount, you first calculate the discount amount which is 30% of $472. 30% of $472 is $141.60. To find the sale price, you subtract the discount amount from the original price: $472 - $141.60 = $330.40. Therefore, the sale price of the television after a 30% discount would be $330.40. Choices A, B, and C are incorrect as they do not accurately reflect the calculated sale price after the discount.

5. What is the median of Pernell's scores (81, 92, 87, 89, and 94)?

• A. 87
• B. 89
• C. 92
• D. 94

Correct answer: B

Rationale: To find the median, we first need to arrange the scores in ascending order: 81, 87, 89, 92, 94. Since there are five scores, the middle score would be the third one, which is 89. Hence, the median of Pernell's scores is 89. Choice A (87) is incorrect because it is the second score in the ordered list, not the middle one. Choice C (92) and Choice D (94) are also incorrect as they are not positioned in the middle of the ordered series.

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