Nursing Elites

1. A taxi service charges $50 for the first mile, $50 for each additional mile, and 20¢ per minute of waiting time. Joan took a cab from her place to a flower shop 8 miles away, where she bought a bouquet, then another 6 miles to her mother's place. The driver had to wait 9 minutes while she bought the bouquet. What was the fare?

• A. $650
• B. $710
• C. $701.80
• D. $650

Correct answer: C

Rationale: To calculate the fare, first, determine the cost for the distance traveled. Joan traveled a total of 14 miles (8 miles to the flower shop + 6 miles to her mother's place). The first mile costs $50, and the remaining 13 miles cost $50 each, totaling $700 for the distance. Additionally, the driver waited for 9 minutes, which incurs an additional cost of $1.80 (9 minutes x $0.20 per minute). Therefore, the total fare is calculated as: Cost for distance + Cost for waiting time = $50 + $650 + $1.80 = $701.80. Choice A, $650, is incorrect as it does not consider the waiting time cost. Choice B, $710, is incorrect as it does not accurately calculate the total fare. Choice D, $650, is incorrect for the same reason as Choice A. The correct total fare is $701.80.

2. Apply the polynomial identity to rewrite (a + b)².

• A. a² + b²
• B. 2ab
• C. a² + 2ab + b²
• D. a² - 2ab + b²

Correct answer: C

Rationale: When you see something like (a + b)², it means you're multiplying (a + b) by itself: (a + b)² = (a + b) × (a + b) To expand this, we use the distributive property (which says you multiply each term in the first bracket by each term in the second bracket): Multiply the first term in the first bracket (a) by both terms in the second bracket: a × a = a² a × b = ab Multiply the second term in the first bracket (b) by both terms in the second bracket: b × a = ab b × b = b² Now, add up all the results from the multiplication: a² + ab + ab + b² Since ab + ab is the same as 2ab, we can simplify it to: a² + 2ab + b² So, (a + b)² = a² + 2ab + b². This is known as a basic polynomial identity, and it shows that when you square a binomial (a two-term expression like a + b), you get three terms: the square of the first term (a²), twice the product of the two terms (2ab), and the square of the second term (b²). Therefore, the correct answer is C (a² + 2ab + b²)

3. A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?

• A. 56
• B. 244
• C. 488
• D. 672

Correct answer: C

Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.

4. Round 8.067 to the nearest tenth.

• A. 8.1
• B. 8.1
• C. 8
• D. 8.11

Correct answer: A

Rationale: To round 8.067 to the nearest tenth, you look at the digit in the hundredth place, which is 6. Since 6 is equal to or greater than 5, you round up the digit in the tenth place. Therefore, 8.067 rounded to the nearest tenth is 8.1. Choice B (8.1) is incorrect as it duplicates the correct answer. Choice C (8) is incorrect as it does not account for the decimal part. Choice D (8.11) is incorrect as it rounds the number to the nearest hundredth, not the nearest tenth.

5. Given the histograms shown below, which of the following statements is true?

• A. Group A is negatively skewed and has a mean less than Group B.
• B. Group A is positively skewed and has a mean greater than Group B.
• C. Group B is negatively skewed and has a mean greater than Group A.
• D. Group B is positively skewed and has a mean less than Group A.

Correct answer: C

Rationale: The correct answer is C. Group B is negatively skewed, indicating more high scores, leading to a higher mean for Group B when compared to Group A. Choice A is incorrect because Group A is not negatively skewed and doesn't have a mean less than Group B. Choice B is incorrect as Group A is not positively skewed and its mean is not greater than Group B. Choice D is also incorrect because Group B having a mean less than Group A contradicts the fact that Group B has a higher mean due to being negatively skewed.

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