Nursing Elites

1. How many feet are in a mile?

• A. 1,000 ft
• B. 5,280 ft
• C. 2,000 ft
• D. 10,000 ft

Correct answer: B

Rationale: The correct answer is B: 5,280 feet in a mile. This is a standard conversion used in the Imperial system of measurement. Choice A, 1,000 ft, is incorrect as it is a common misconception and not the accurate conversion. Choice C, 2,000 ft, is also incorrect. Choice D, 10,000 ft, is significantly higher than the actual conversion and is incorrect. Remember, when converting miles to feet, the accurate value is 5,280 feet in a mile.

2. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?

• A. 3/12
• B. 3/55
• C. 2/10
• D. 1/3

Correct answer: B

Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.

3. Which of the following is the correct solution to the equation 3x + 4 = 19?

• A. x = 3
• B. x = 4
• C. x = 5
• D. x = 6

Correct answer: C

Rationale: To solve the equation 3x + 4 = 19, first, subtract 4 from both sides to isolate the term with x, which gives 3x = 15. Then, divide both sides by 3 to solve for x, resulting in x = 5. Therefore, the correct answer is x = 5. Choice A, x = 3, is incorrect as it does not satisfy the equation. Choice B, x = 4, is also incorrect as it does not make the equation true. Choice D, x = 6, is incorrect as it does not align with the correct solution obtained through the proper algebraic steps.

4. Three roommates decided to combine their money to buy a birthday gift for the fourth roommate. The first roommate contributed $12.03, the second roommate gave $11.96, and the third roommate donated $12.06. Estimate the total amount of money the roommates used to purchase the gift

• A. $34
• B. $35
• C. $36
• D. $37

Correct answer: C

Rationale: To find the total amount contributed, you can add the individual contributions: $12.03 + $11.96 + $12.06 = $36. Therefore, the roommates used a total of $36 to purchase the gift. Choice A ($34), B ($35), and D ($37) are incorrect as they do not reflect the accurate total amount contributed by the roommates.

5. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

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