HESI LPN
HESI Fundamentals Study Guide
1. A healthcare professional is assessing a patient's skin. Which patient is most at risk for impaired skin integrity?
- A. A patient who is afebrile
- B. A patient who is diaphoretic
- C. A patient with strong pedal pulses
- D. A patient with adequate skin turgor
Correct answer: B
Rationale: Excessive moisture on the skin, as seen in a diaphoretic patient, can lead to impaired skin integrity. Diaphoresis softens epidermal cells, promotes bacterial growth, and can cause skin maceration. Afebrile status, strong pedal pulses, and adequate skin turgor are not directly associated with an increased risk of impaired skin integrity. Afebrile indicates the absence of fever, not a risk to skin integrity. Strong pedal pulses suggest good circulation, which is beneficial for skin health. Adequate skin turgor is a sign of good hydration and skin elasticity, indicating a lower risk of impaired skin integrity.
2. A client with heart failure is being taught by a nurse on reducing daily sodium intake. Which factor is most crucial in determining the client’s ability to learn new dietary habits?
- A. The client's involvement in planning the change
- B. The cost of the dietary changes
- C. The availability of low-sodium foods
- D. The client’s previous dietary knowledge
Correct answer: D
Rationale: The client’s previous dietary knowledge is the most critical factor in determining the ability to learn new dietary habits. Understanding the client's existing dietary knowledge helps tailor the teaching to build upon what they already know. While client involvement in planning changes can increase adherence and motivation, the foundational knowledge is essential for effective learning. The cost of dietary changes and the availability of low-sodium foods are important considerations but not as crucial as the client's existing knowledge.
3. A client with a diagnosis of myocardial infarction (MI) is being treated. Which laboratory value would be most concerning?
- A. Troponin level of 0.5 ng/mL
- B. Creatine kinase-MB (CK-MB) of 5.0 ng/mL
- C. Serum potassium of 4.5 mEq/L
- D. Blood glucose of 180 mg/dL
Correct answer: A
Rationale: A troponin level of 0.5 ng/mL is elevated, indicating myocardial damage, making it the most concerning finding in a client with a myocardial infarction (MI). Troponin is a highly specific marker for cardiac muscle damage, and elevated levels suggest ongoing injury to the heart muscle. While Creatine kinase-MB (CK-MB) is also a cardiac enzyme, troponin is more specific and sensitive for myocardial damage. Serum potassium and blood glucose levels are important parameters to monitor in MI patients, but in this scenario, the elevated troponin level takes precedence as it directly reflects cardiac injury.
4. A nurse is providing home care for a client who is receiving tube feedings and medication through a gastrostomy tube. The family member providing the feedings reports that the client has begun to have diarrhea. For which of the following practices should the nurse intervene?
- A. The family member washes out the feeding bag with warm water once every 24 hours.
- B. The family member washes out the feeding bag with hot water once every 24 hours.
- C. The family member washes out the feeding bag with soap and water every 24 hours.
- D. The family member changes the feeding bag every 24 hours.
Correct answer: A
Rationale: The correct answer is A. Washing out the feeding bag with warm water once every 24 hours is not sufficient to prevent bacterial growth and can lead to diarrhea. Using hot water may damage the feeding bag. Washing out the feeding bag with soap and water every 24 hours is excessive and may leave residue that could be harmful. Changing the feeding bag every 24 hours is important for preventing infections but does not directly address the issue of diarrhea in this case.
5. A nurse is calculating a client's fluid intake over the past 8 hr. Which of the following items should the nurse plan to document on the client's intake and output record as 120 mL of fluid?
- A. 2 cups of soup
- B. 1 quart of water
- C. 8 oz of ice chips
- D. 6 oz of tea
Correct answer: C
Rationale: The correct answer is C: 8 oz of ice chips. When calculating fluid intake, the nurse should document half of the volume of ice chips to account for the air in between the chips. Therefore, 8 oz of ice chips equals 120 mL of fluid. Choices A, B, and D are incorrect because they do not equate to 120 mL of fluid intake as per the given scenario. Choice A, 2 cups of soup, is more than 120 mL. Choice B, 1 quart of water, is significantly more than 120 mL. Choice D, 6 oz of tea, is less than 120 mL.
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