Nursing Elites

1. A client with hyperthyroidism is prescribed methimazole. Which adverse effect should the nurse monitor for?

• A. Agranulocytosis
• B. Hypoglycemia
• C. Bradycardia
• D. Hypercalcemia

Correct answer: A

Rationale: The correct answer is Agranulocytosis. Methimazole, used to treat hyperthyroidism, can lead to agranulocytosis, a severe decrease in white blood cells. This condition increases the risk of infections and requires immediate medical attention. Hypoglycemia (choice B) is not a common adverse effect of methimazole. Bradycardia (choice C) is unlikely as methimazole tends to have minimal effects on heart rate. Hypercalcemia (choice D) is not associated with methimazole use.

2. An unlicensed assistive personnel (UAP) reports to the nurse that a client with a postoperative wound infection has a temperature of 103.8°F, blood pressure 90/70, pulse 124 beats/min, and respirations of 28 breaths/min. When the nurse assesses the client's findings, they include a mottled skin appearance and confusion. Which action should the nurse take first?

• A. Obtain a wound specimen for culture.
• B. Initiate an infusion of intravenous (IV) fluids.
• C. Transfer the client to the ICU.
• D. Assess the client's core temperature.

Correct answer: B

Rationale: The correct action for the nurse to take first is to initiate an infusion of intravenous (IV) fluids. In this scenario, the client is showing signs of sepsis, indicated by a high temperature, low blood pressure, rapid heart rate, and increased respiratory rate. Mottled skin appearance and confusion are also signs of poor perfusion. Initiating IV fluids is crucial in treating sepsis to maintain blood pressure and perfusion. Obtaining a wound specimen for culture (Choice A) can be important but is not the priority at this moment. Transferring the client to the ICU (Choice C) can be considered after stabilizing the client. Assessing the client's core temperature (Choice D) is not the immediate priority compared to addressing the signs of sepsis and poor perfusion.

3. A client who is newly diagnosed with emphysema is being prepared for discharge. Which instruction is best for the nurse to provide the client to assist them with dyspnea self-management?

• A. Allow additional time to complete physical activities to reduce oxygen demand.
• B. Practice inhaling through the nose and exhaling slowly through pursed lips.
• C. Use a humidifier to increase home air quality humidity between 30-50%.
• D. Strengthen abdominal muscles by alternating leg raises during exhalation.

Correct answer: B

Rationale: The correct answer is B. Instructing the client to practice inhaling through the nose and exhaling slowly through pursed lips can help improve oxygenation and reduce dyspnea. This technique, known as pursed lip breathing, can help regulate breathing patterns and decrease the work of breathing in clients with emphysema. Choice A is incorrect because allowing additional time for physical activities does not directly address dyspnea management. Choice C is incorrect as using a humidifier, although beneficial for respiratory conditions, does not specifically assist with dyspnea self-management. Choice D is also incorrect as strengthening abdominal muscles through leg raises does not directly target dyspnea relief.

4. A client with fluid volume excess has gained 6.6 pounds. The nurse recognizes that this is equivalent to what volume of fluid?

• A. Two liters.
• B. Three liters.
• C. Four liters.
• D. Five liters.

Correct answer: B

Rationale: A weight gain of 6.6 pounds is approximately equivalent to 3 liters of fluid. It is important to remember that 1 liter of fluid is equal to 1 kg, which is approximately 2.2 pounds. Therefore, when the client gains 6.6 pounds, it translates to 3 liters of fluid. Choices A, C, and D are incorrect as they do not align with the conversion rate of 1 liter of fluid to 2.2 pounds.

5. The nurse instructs the mother of a child with a ventricular septal defect that she can expect the child to become cyanotic when the child does what?

• A. Experiences an elevation in temperature.
• B. Sleeps on the left side.
• C. Cries vigorously.
• D. Eats.

Correct answer: C

Rationale: The correct answer is C: Cries vigorously. When the child cries vigorously, it increases the pressure in the right ventricle, allowing unoxygenated blood to enter the circulating volume, leading to cyanosis. This occurs due to the shunting of blood from the right side of the heart to the left side through the ventricular septal defect. Choices A, B, and D are incorrect because they do not directly impact the pressure in the right ventricle, which is crucial in causing cyanosis in this scenario.

Similar Questions