Nursing Elites

1. A client is being treated for diabetic ketoacidosis (DKA). Which laboratory value would be most concerning?

• A. Blood glucose of 350 mg/dL
• B. Serum bicarbonate of 18 mEq/L
• C. Arterial pH of 7.20
• D. Serum potassium of 5.5 mEq/L

Correct answer: C

Rationale: In a client with diabetic ketoacidosis (DKA), the most concerning laboratory value is an arterial pH of 7.20. An arterial pH of 7.20 indicates severe acidosis, which is a critical condition requiring immediate intervention. This pH level reflects a significant imbalance in the body's acid-base status, potentially leading to serious complications. High blood glucose levels (choice A) are expected in DKA but do not directly indicate the severity of acidosis. A serum bicarbonate level of 18 mEq/L (choice B) is low but not as immediately critical as a pH of 7.20. Serum potassium of 5.5 mEq/L (choice D) is elevated, which can occur in DKA due to insulin deficiency, but it is not the most concerning value in this scenario.

2. A child weighing 20 kg has a new prescription for cefoxitin at 80 mg/kg/day administered intravenously every 6 hours. How much cefoxitin should be administered with each dose?

• A. 400 mg
• B. 200 mg
• C. 1600 mg
• D. 100 mg

Correct answer: A

Rationale: To determine the amount of cefoxitin to be administered with each dose, first, calculate the total daily dose by multiplying the child's weight (20 kg) by the prescribed dose (80 mg/kg/day): 80 mg/kg/day × 20 kg = 1600 mg/day. Since the medication is administered every 6 hours (4 doses/day), divide the total daily dose by the number of doses: 1600 mg / 4 = 400 mg. Therefore, each dose should be 400 mg. Choice B (200 mg) is incorrect because it is half the calculated dose. Choice C (1600 mg) is incorrect as it represents the total daily dose, not the dose per administration. Choice D (100 mg) is incorrect as it is a quarter of the calculated dose.

3. When providing hygiene for an older-adult patient, why does the nurse closely assess the skin?

• A. Outer skin layer becomes less resilient.
• B. Less frequent bathing may be required.
• C. Skin becomes more subject to bruising.
• D. Sweat glands become less active.

Correct answer: B

Rationale: The correct answer is B: 'Less frequent bathing may be required.' In older adults, daily bathing or using hot water and harsh soap can lead to excessively dry skin. Therefore, the nurse closely assesses the skin to determine if less frequent bathing is necessary to prevent skin dryness and maintain skin integrity. Choice A is incorrect because the outer skin layer does not become less resilient with age. Choice C is incorrect as aging skin is actually more prone to bruising due to thinning of the skin. Choice D is incorrect because sweat gland activity generally decreases with age, leading to reduced skin moisture rather than increased activity.

4. When assessing a client with wrist restraints, the nurse observes that the fingers on the right hand are blue. What action should the nurse implement first?

• A. Loosen the right wrist restraint.
• B. Apply a pulse oximeter to the right hand.
• C. Compare hand color bilaterally.
• D. Palpate the right radial pulse.

Correct answer: A

Rationale: The correct action to take first when observing blue fingers in a client with wrist restraints is to loosen the right wrist restraint. Blue fingers indicate compromised circulation, and loosening the restraint can help restore blood flow to the area. Applying a pulse oximeter (Choice B) or palpating the right radial pulse (Choice D) may be necessary following the loosening of the restraint to assess the client's oxygen saturation and pulse. Comparing hand color bilaterally (Choice C) is important but not the immediate action needed when a circulation issue is noted in one hand.

5. During an abdominal examination, a nurse in a provider’s office determines that a client has abdominal distention. The protrusion is at midline, the skin over the area is taut, and the nurse notes no involvement of the flanks. Which of the following possible causes of distention should the nurse suspect?

• A. Fat
• B. Fluid
• C. Flatus
• D. Hernias

Correct answer: D

Rationale: The correct answer is 'Hernias.' Abdominal distention with a midline protrusion, taut skin, and no involvement of the flanks is characteristic of hernias. Hernias are caused by a weakness in the abdominal wall, allowing organs or tissues to protrude through. Fluid accumulation (ascites) typically presents with a more generalized distention, while fat accumulation may cause more diffuse distension rather than a focal midline protrusion. Flatus, or gas, would not typically present with a visible midline protrusion and taut skin like hernias.

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