Nursing Elites

1. Which measure for the center of a small sample set would be most affected by outliers?

• A. Mean
• B. Median
• C. Mode
• D. None of the above

Correct answer: A

Rationale: The mean is calculated by summing all values in a dataset and then dividing by the total number of values. Outliers, which are data points significantly different from the other values, can greatly impact the mean because they affect the sum. The mean is sensitive to extreme values, making it the measure for the center of a small sample set most affected by outliers. The median, on the other hand, is not influenced by outliers as it represents the middle value when the data points are ordered. The mode is the value that appears most frequently in the dataset and is not directly influenced by outliers. Therefore, the correct answer is the mean, as it is highly influenced by outliers in a small sample set.

2. A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?

• A. 24
• B. 28
• C. 36
• D. 38

Correct answer: C

Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.

3. If you pull an orange block from a bag of 3 orange, 5 green, and 4 purple blocks, what is the probability of consecutively pulling two more orange blocks without replacement?

• A. 1/12
• B. 3/55
• C. 1/55
• D. 2/33

Correct answer: B

Rationale: To calculate the probability of pulling two more orange blocks consecutively without replacement after the initial orange block is pulled, we need to multiply the probabilities. After the first orange block is pulled, there are 2 orange blocks left out of a total of 11 blocks remaining. So, the probability of pulling a second orange block is 2/11. Therefore, the overall probability is (3/12) * (2/11) = 3/55. Choice A (1/12) is incorrect because it only considers the probability of the first orange block being pulled. Choice C (1/55) is incorrect as it represents the probability of pulling two orange blocks in a row, not the consecutive pulls after the initial pull. Choice D (2/33) is incorrect as it does not reflect the correct calculation for the consecutive pulls of orange blocks.

4. What is the result of (6.4)(2.8) ÷ 0.4? Which of the following is correct?

• A. 16.62
• B. 17.92
• C. 41.55
• D. 44.8

Correct answer: D

Rationale: To simplify the expression, first multiply 6.4 by 2.8 to get 17.92. Then, divide the result by 0.4 to find the final answer. Therefore, (6.4)(2.8) ÷ 0.4 equals 44.8. Choices A, B, and C are incorrect because they do not represent the correct result of the given expression.

5. As part of a study, a set of patients will be divided into three groups. 4/15 of the patients will be in Group Alpha, 2/5 in Group Beta, and 1/3 in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.

• A. Group Alpha, Group Beta, Group Gamma
• B. Group Alpha, Group Gamma, Group Beta
• C. Group Gamma, Group Alpha, Group Beta
• D. Group Alpha, Group Beta, Group Gamma

Correct answer: B

Rationale: The correct order is Group Alpha, Group Gamma, Group Beta based on the common denominators of the fractions. To determine the order from smallest to largest, compare the fractions' numerators since the denominators are different. Group Alpha has 4/15 patients, Group Gamma has 1/3 patients, and Group Beta has 2/5 patients. Comparing the fractions' numerators, the order from smallest to largest is Group Alpha (4), Group Gamma (1), and Group Beta (2). Therefore, the correct order is Group Alpha, Group Gamma, Group Beta. Choice A is incorrect as it lists Group Beta before Group Gamma. Choice C is incorrect as it lists Group Gamma before Group Alpha. Choice D is incorrect as it lists Group Beta before Group Gamma, which is not in ascending order based on the number of patients.

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