Nursing Elites

1. What property of a substance refers to its ability to be drawn into thin wires?

• A. Conductivity
• B. Ductility
• C. Viscosity
• D. Malleability

Correct answer: B

Rationale: Ductility is the property of a substance that allows it to be drawn into thin wires without breaking. Conductivity refers to the ability of a substance to conduct electricity or heat, not to be drawn into wires. Viscosity is the measure of a fluid's resistance to flow, not related to the ability to be drawn into wires. Malleability is the property of a substance that allows it to be hammered or rolled into thin sheets, not specifically related to being drawn into wires. Therefore, the correct property for the ability to be drawn into thin wires is ductility.

2. When baking soda (sodium bicarbonate) reacts with vinegar (acetic acid), what type of reaction occurs?

• A. Combustion
• B. Double displacement
• C. Decomposition
• D. Synthesis

Correct answer: B

Rationale: When baking soda (sodium bicarbonate) reacts with vinegar (acetic acid), a double displacement reaction occurs. In this reaction, the positive ions in baking soda switch places with the positive ions in vinegar to form water, carbon dioxide, and a salt. Combustion involves a reaction with oxygen to produce heat and light energy. Decomposition is the breakdown of a compound into simpler substances, which is not the case in the given reaction. Synthesis is the combination of substances to form a more complex compound, which is also not the type of reaction observed when baking soda and vinegar react.

3. What happens to the frequency of a wave if its wavelength decreases while the speed remains constant?

• A. Frequency decreases
• B. Frequency increases
• C. Frequency remains constant
• D. Frequency becomes zero

Correct answer: B

Rationale: The correct answer is B: Frequency increases. Frequency and wavelength are inversely proportional in a wave with a constant speed. When the wavelength decreases while the speed remains constant, the frequency must increase to maintain the constant speed of the wave. This relationship is governed by the equation: speed = frequency x wavelength. Choice A is incorrect as frequency increases when wavelength decreases. Choice C is incorrect as the frequency changes in this scenario. Choice D is incorrect as the frequency does not become zero but increases when the wavelength decreases.

4. What is the relationship between the frequency and period of a wave?

• A. They are unrelated
• B. Frequency = Period
• C. Frequency = 1/Period
• D. Period = 1/Frequency

Correct answer: D

Rationale: The correct relationship between frequency and period of a wave is that Period = 1/Frequency. This relationship indicates that the period of a wave is the reciprocal of its frequency. Frequency refers to the number of complete cycles of a wave occurring in a unit of time, while the period is the time taken for one complete cycle of the wave to occur. As frequency and period are inversely related, the correct formula to express this relationship is Period = 1/Frequency. Choice A is incorrect as frequency and period are related. Choice B is incorrect as frequency and period are not equal. Choice C is incorrect as it suggests that frequency is directly proportional to period, which is not the case.

5. Two mice are both heterozygous for two traits: white fur (Ww) and short fur (Ss). Their offspring are most likely to have which of the following genotypes for these traits?

• A. wwss
• B. WWSS
• C. WwSs
• D. WWSs

Correct answer: C

Rationale: When two mice that are heterozygous for white fur (Ww) and short fur (Ss) mate, they can produce offspring with different combinations of the two traits. The Punnett square for this cross shows that the most likely genotype for the offspring is WwSs. In this case, each offspring receives one allele for white fur (W) and one for short fur (S) from each parent, resulting in a heterozygous genotype for both traits. Choice A (wwss) is incorrect as it represents a homozygous recessive genotype for both traits. Choice B (WWSS) is also incorrect as it represents a homozygous dominant genotype for both traits. Choice D (WWSs) is incorrect as it represents a genotype where one trait is homozygous dominant (W) and the other is heterozygous (S), which is not the most likely outcome based on the given parental genotypes.

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