ATI TEAS 7
Math Practice TEAS Test
1. How can you visually differentiate between a histogram and a bar graph?
- A. A bar graph has gaps between the bars; a histogram does not
- B. A bar graph displays frequency; a histogram does not
- C. A histogram illustrates comparison; a bar graph does not
- D. A bar graph includes labels; a histogram does not
Correct answer: A
Rationale: The key difference between a histogram and a bar graph is that a bar graph has gaps between the bars, while a histogram does not. This feature helps in visually distinguishing between the two. Choice B is incorrect because both types of graphs can show frequency. Choice C is incorrect as both graphs can be used for comparison. Choice D is incorrect as both types of graphs can have labels for better understanding.
2. What is the percentage equivalent of 0.0016?
- A. 16%
- B. 160%
- C. 1.60%
- D. 0.16%
Correct answer: D
Rationale: To convert a decimal to a percentage, you multiply by 100. Therefore, to find the percentage equivalent of 0.0016, you would multiply 0.0016 by 100 to get 0.16%. This means that choice D, '0.16%', is the correct answer. Choices A, B, and C are incorrect because they do not correctly represent the percentage equivalent of 0.0016.
3. After taking a certain antibiotic, Dr. Lee observed that 30% of all his patients developed an infection. He further noticed that 5% of those patients required hospitalization to recover from the infection. What percentage of Dr. Lee’s patients were hospitalized after taking the antibiotic?
- A. 1.50%
- B. 5%
- C. 15%
- D. 30%
Correct answer: A
Rationale: To find the percentage of Dr. Lee's patients hospitalized, you need to calculate 5% of the 30% who developed an infection. 5% of 30% is 1.5%. Therefore, 1.5% of Dr. Lee's patients were hospitalized. Choice A is correct. Choices B, C, and D are incorrect because they do not accurately reflect the calculation of the percentage of patients requiring hospitalization after taking the antibiotic.
4. Between the years 2000 and 2010, the number of births in the town of Daneville increased from 1432 to 2219. What is the approximate percent increase in the number of births?
- A. 55%
- B. 36%
- C. 64%
- D. 42%
Correct answer: A
Rationale: To calculate the percent increase, subtract the initial value from the final value, which gives 2219 - 1432 = 787. Then, divide the increase (787) by the initial value (1432) and multiply by 100 to get the percentage: (787/1432) * 100 = 55%. Therefore, the approximate percent increase in the number of births is 55%. Choice B, 36%, is incorrect because it does not match the calculated increase. Choice C, 64%, is incorrect as it is higher than the actual percentage. Choice D, 42%, is incorrect as it is lower than the actual percentage.
5. What is the sum of two odd numbers, two even numbers, and an odd number and an even number?
- A. Odd + Odd = Even; Even + Even = Even; Odd + Even = Odd
- B. Odd + Odd = Odd; Even + Even = Even; Odd + Even = Even
- C. Odd + Odd = Even; Even + Even = Odd; Odd + Even = Even
- D. Odd + Odd = Odd; Even + Even = Odd; Odd + Even = Even
Correct answer: A
Rationale: The sum of two odd numbers is even because odd numbers have a difference of 1 and adding them results in a multiple of 2. The sum of two even numbers is even because even numbers are multiples of 2. When an odd number and an even number are added, the result is odd because the even number contributes an extra 1 to the sum, making it an odd number. Therefore, the correct answer is A. Choices B, C, and D have incorrect combinations of the sum of odd and even numbers.
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