ATI TEAS 7
ATI TEAS Math Practice Test
1. University Q has an extremely competitive nursing program. Historically, 3/4 of the students in each incoming class major in nursing, but only 1/5 of those who major in nursing complete the program. If this year’s incoming class has 100 students, how many will complete the nursing program?
- A. 75
- B. 20
- C. 15
- D. 5
Correct answer: C
Rationale: Out of the 100 students, 3/4 major in nursing, which equals 75 students. However, only 1/5 of these 75 students will complete the program. Calculating 1/5 of 75 gives us 15 students who will complete the nursing program. Therefore, the correct answer is 15. Choice A (75) is incorrect as it represents the total number of students majoring in nursing, not completing the program. Choices B (20) and D (5) are incorrect calculations and do not align with the information provided in the question.
2. Which of the following statements is true?
- A. The mean is less than the median
- B. The mode is greater than the median
- C. The mode is less than the mean, median, and range
- D. The mode is equal to the range
Correct answer: A
Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.
3. Tom needs to buy ink cartridges and printer paper. Each ink cartridge costs $30. Each ream of paper costs $5. He has $100 to spend. Which of the following inequalities may be used to find the combinations of ink cartridges and printer paper he may purchase?
- A. 30c + 5p ≤ 100
- B. 30c + 5p = 100
- C. 30c + 5p > 100
- D. 30c + 5p < 100
Correct answer: A
Rationale: The correct inequality is 30c + 5p ≤ 100. This represents the combinations of ink cartridges (c) and printer paper (p) that Tom may purchase, ensuring the total cost is less than or equal to $100. Choice B is incorrect because the total cost should be less than or equal to $100, not equal to. Choices C and D are also incorrect as they indicate the total cost being greater than $100, which is not the case given Tom's budget limit.
4. If 1 inch on a map represents 60 ft, how many yards apart are two points if the distance between the points on the map is 10 inches?
- A. 1800
- B. 600
- C. 200
- D. 2
Correct answer: B
Rationale: If 1 inch on the map represents 60 ft, then for 10 inches on the map, the actual distance would be 10 inches x 60 ft = 600 ft. To convert this to yards, we know that 1 yard equals 3 feet. Therefore, the distance between the two points is 600 ft / 3 ft/yard = 200 yards. Choice A (1800) is incorrect because it incorrectly multiplies by 10 again instead of converting to yards. Choice C (200) is incorrect because it fails to adjust the measurement from feet to yards. Choice D (2) is incorrect as it does not consider the correct conversion factor from feet to yards.
5. Two even integers and one odd integer are multiplied together. Which of the following could be their product?
- A. 3.75
- B. 9
- C. 16.2
- D. 24
Correct answer: D
Rationale: When multiplying two even integers and one odd integer, the product will always be even. This is because multiplying any number of even integers will always result in an even number. Therefore, the only possible product from the given options is 24, as it is the only even number listed. Choices A, B, and C are incorrect as they are all odd numbers, and the product of two even integers and one odd integer will never result in an odd number.
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