ATI TEAS 7
TEAS 7 Math Practice Test
1. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?
- A. shifts = 20 + 3 + 1/2
- B. shifts = (20)(3)(1/2)
- C. shifts = (20)(3) + 1/2
- D. shifts = 20 + (3)(1/2)
Correct answer: B
Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.
2. What was the mean time for the women who ran the 200m event at the 2008 Olympic Games (times in seconds: 22.33, 22.50, 22.50, 22.61, 22.71, 22.72, 22.83, 23.22)?
- A. 22.50 sec
- B. 22.66 sec
- C. 22.68 sec
- D. 22.77 sec
Correct answer: C
Rationale: To find the mean time, you need to add all the times (22.33 + 22.50 + 22.50 + 22.61 + 22.71 + 22.72 + 22.83 + 23.22) and then divide by the total number of times (8). This calculation results in a mean time of 22.68 seconds. Choice A, 22.50 sec, is incorrect because it is the time of one of the runners, not the mean time. Choice B, 22.66 sec, and Choice D, 22.77 sec, are also incorrect as they are not the calculated mean of the given times.
3. What is 2.7834 rounded to the nearest tenth?
- A. 2.7
- B. 2.78
- C. 2.8
- D. 2.88
Correct answer: C
Rationale: To round 2.7834 to the nearest tenth, we look at the digit in the hundredths place, which is 8. Since 8 is greater than or equal to 5, the digit in the tenths place is rounded up. Therefore, 2.7834 rounded to the nearest tenth is 2.8. Choice A (2.7) is incorrect because rounding down would require the digit in the hundredths place to be less than 5. Choice B (2.78) is incorrect because rounding to the nearest tenth involves considering the digit in the hundredths place. Choice D (2.88) is incorrect as it goes beyond rounding to just the nearest tenth.
4. Solve for x in the equation above: (x/y) - z = rw
- A. X = y(z + rw)
- B. X = rw(y - z)
- C. X = rwy + z
- D. X = rwy - z
Correct answer: A
Rationale: To solve for x, first, isolate x by moving the term involving x to one side of the equation. Begin by adding z to both sides of the equation to get (x/y) = rw + z. Then, multiply both sides by y to get x = y(rw + z), which simplifies to x = y(z + rw). Therefore, choice A is correct. Choices B, C, and D are incorrect because they do not correctly rearrange the terms in the equation to solve for x.
5. Which of the following best describes the data represented by this scatterplot?
- A. This is a linear association with a positive correlation.
- B. This is a linear association with a negative correlation.
- C. This is a nonlinear association.
- D. There is no association.
Correct answer: A
Rationale: The correct answer is A. The scatterplot depicts a clear linear association with a positive correlation between the two variables. Choice B is incorrect as the correlation is positive, not negative. Choice C is incorrect because the scatterplot does not show a nonlinear association. Choice D is incorrect as there is a distinguishable association present in the data.
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