HESI LPN
Adult Health 2 Exam 1
1. The nurse is providing discharge teaching to a client with newly diagnosed type 2 diabetes mellitus. Which instruction is most important to prevent complications?
- A. Monitor blood glucose levels regularly
- B. Maintain a low-fat diet
- C. Exercise regularly
- D. Take medication as prescribed
Correct answer: A
Rationale: Regular monitoring of blood glucose levels is crucial in managing diabetes and preventing complications. This allows the client and healthcare team to make timely adjustments to the treatment plan. While maintaining a low-fat diet, exercising regularly, and taking medication as prescribed are all important aspects of diabetes management, monitoring blood glucose levels takes precedence as it provides real-time information about the client's condition and helps prevent acute complications.
2. A client with a diagnosis of bipolar disorder is prescribed lithium. Which electrolyte imbalance should the nurse monitor for?
- A. Hyponatremia
- B. Hypokalemia
- C. Hypercalcemia
- D. Hypernatremia
Correct answer: A
Rationale: The correct answer is A: Hyponatremia. Lithium can affect sodium levels in the body, potentially leading to hyponatremia, which is a condition characterized by low sodium levels. This imbalance requires close monitoring as it can lead to symptoms such as confusion, weakness, and even seizures. Choices B, C, and D are incorrect because lithium is not primarily associated with causing hypokalemia, hypercalcemia, or hypernatremia. While these imbalances can occur in certain conditions or with other medications, the main electrolyte imbalance to monitor when a client is prescribed lithium is hyponatremia.
3. The nurse is assessing a newborn and notes that the infant has a yellowish tint to the skin. What should the nurse do next?
- A. Reassure the parents that this is normal
- B. Monitor the infant's bilirubin levels
- C. Increase the frequency of feedings
- D. Administer phototherapy
Correct answer: B
Rationale: When a newborn presents with a yellowish tint to the skin, it can indicate jaundice, which is caused by elevated bilirubin levels. Monitoring the infant's bilirubin levels is crucial to assess the severity of jaundice and determine the need for further intervention. Reassuring the parents without proper assessment could lead to delayed treatment if jaundice is present. Increasing the frequency of feedings may not address the underlying cause of jaundice. Administering phototherapy is a treatment option that should be based on bilirubin level assessment and healthcare provider's recommendation.
4. The nurse is preparing to administer a tuberculin skin test (TST). Which area of the body is the preferred site for this injection?
- A. Deltoid muscle
- B. Inner forearm
- C. Abdomen
- D. Thigh
Correct answer: B
Rationale: The inner forearm is the preferred site for administering a tuberculin skin test (TST) due to its easy accessibility, minimal hair interference, and good visibility of the injection site, allowing for accurate interpretation of the test results. The deltoid muscle, abdomen, and thigh are not preferred sites for a TST as they may not provide the optimal conditions required for the test. The deltoid muscle is commonly used for intramuscular injections, the abdomen may have varying subcutaneous fat thickness affecting the test, and the thigh may not provide the necessary visibility for accurate reading.
5. The practical nurse is preparing to administer a prescription for cefazolin (Kefzol) 600 mg IM every six hours. The available vial is labeled, 'Cefazolin (Kefzol) 1 gram,' and the instructions for reconstitution state, 'For IM use add 2 ml sterile water for injection. Total volume after reconstitution = 2.5 ml.' When reconstituted, how many milligrams are in each milliliter of solution?
- A. 400 mg/mL
- B. 500 mg/mL
- C. 450 mg/mL
- D. 350 mg/mL
Correct answer: A
Rationale: After reconstitution, the concentration of cefazolin solution is calculated by dividing the total amount of drug (600 mg) by the total volume after reconstitution (2.5 mL). This gives 600 mg / 2.5 mL = 240 mg/mL. However, the question asks for the concentration in each milliliter of solution after reconstitution, so we need to consider the final volume of 2.5 mL. Therefore, 240 mg/mL * 2.5 mL = 600 mg, which means each milliliter contains 240 mg of cefazolin. Therefore, after reconstitution, there are 400 mg of cefazolin in each milliliter of solution. Choices B, C, and D are incorrect as they do not accurately reflect the concentration after reconstitution.
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