mesosomes are the internal extensions of which of the following

ATI TEAS 7

Practice Science TEAS Test

1. Mesosomes are the internal extensions of which of the following?

A. Capsule
B. Cell membranes
C. Cell wall
D. Chromatin body

Correct answer: B

Rationale: Mesosomes are the internal extensions of the cell membrane, not the capsule, cell wall, or chromatin body. They play a crucial role in cell division and are essential for various cellular processes such as respiration and cell wall formation. Mesosomes are not associated with the capsule (choice A), cell wall (choice C), or chromatin body (choice D), making these options incorrect.

2. How many amino acids can make up a protein?

A. 10-20
B. 50-100
C. 100-500
D. 1000+

Correct answer: A

Rationale: Proteins are made up of long chains of amino acids, and there are 20 standard amino acids commonly found in proteins. The sequence and arrangement of these amino acids determine the structure and function of a protein. While proteins can vary in size and complexity, the number of amino acids typically ranges from around 10 to 20 in smaller proteins to hundreds or even thousands in larger proteins. Therefore, the range of 10-20 amino acids is the most accurate representation of the number of amino acids that can make up a protein. Choices B, C, and D are incorrect as they provide ranges that are beyond the typical number of amino acids found in proteins and may lead to confusion. The correct answer is A (10-20).

3. Which human body system is correctly matched with its function?

A. Respiratory system; exchanges oxygen and carbon dioxide in the lungs.
B. Circulatory system; transports oxygen to cells and removes carbon dioxide.
C. Lymphatic system; produces antibodies that destroy virally affected or foreign cells.
D. Endocrine system; regulates hormones controlling bodily functions and metabolism.

Correct answer: B

Rationale: The circulatory system is responsible for the transportation of oxygen from the lungs to all the body's cells and tissues, as well as removing carbon dioxide from the cells and transporting it back to the lungs to be exhaled. This process is crucial for cellular respiration and the exchange of gases necessary for bodily functions. Choice B accurately matches the role of the circulatory system by describing its function of transporting oxygen to cells and removing carbon dioxide, which is essential for maintaining proper cellular activities. Choices A, C, and D are incorrect because they do not accurately match the body system with its function. The respiratory system primarily involves the exchange of gases in the lungs, not transportation to cells; the lymphatic system deals with immunity through the production of antibodies, not gas exchange; and the endocrine system's main function is hormone regulation, not the transport of gases.

4. Which of the following is NOT a type of epithelium?

A. Stratified squamous
B. Simple cuboidal
C. Stratified columnar
D. Pseudostratified columnar

Correct answer: D

Rationale: The correct answer is D, Pseudostratified columnar. Pseudostratified columnar epithelium is not a type of epithelium. It is a specialized form of simple columnar epithelium. Stratified squamous, simple cuboidal, and stratified columnar are all types of epithelial tissues found in the human body. Stratified squamous epithelium is found in the skin, mouth, and esophagus; simple cuboidal epithelium lines kidney tubules and glands; stratified columnar epithelium is present in parts of the respiratory tract and male urethra.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

A. 18.3 g
B. 19.7 g
C. 21.0 g
D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.