ATI TEAS 7
TEAS 7 Math Practice Test
1. As part of a study, a set of patients will be divided into three groups. 4/15 of the patients will be in Group Alpha, 2/5 in Group Beta, and 1/3 in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.
- A. Group Alpha, Group Beta, Group Gamma
- B. Group Alpha, Group Gamma, Group Beta
- C. Group Gamma, Group Alpha, Group Beta
- D. Group Alpha, Group Beta, Group Gamma
Correct answer: B
Rationale: The correct order is Group Alpha, Group Gamma, Group Beta based on the common denominators of the fractions. To determine the order from smallest to largest, compare the fractions' numerators since the denominators are different. Group Alpha has 4/15 patients, Group Gamma has 1/3 patients, and Group Beta has 2/5 patients. Comparing the fractions' numerators, the order from smallest to largest is Group Alpha (4), Group Gamma (1), and Group Beta (2). Therefore, the correct order is Group Alpha, Group Gamma, Group Beta. Choice A is incorrect as it lists Group Beta before Group Gamma. Choice C is incorrect as it lists Group Gamma before Group Alpha. Choice D is incorrect as it lists Group Beta before Group Gamma, which is not in ascending order based on the number of patients.
2. Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90. How much does one box of crackers cost?
- A. $1.75
- B. $2.00
- C. $2.25
- D. $2.50
Correct answer: C
Rationale: To solve this problem, we can set up a system of equations. Let the cost of one container of yogurt be y and the cost of one box of crackers be c. From the first scenario, we have 4y + 3c = 9.55. From the second scenario, we have 2y + 2c = 5.90. Solving these equations simultaneously, we find that c = $2.25. Therefore, one box of crackers costs $2.25. Choice A, $1.75, is incorrect because it does not satisfy the given conditions in the system of equations. Choice B, $2.00, is incorrect as it does not match the calculated solution. Choice D, $2.50, is incorrect as it does not align with the calculated value for one box of crackers.
3. Half of a circular garden with a radius of 11.5 feet needs weeding. Find the area in square feet that needs weeding. Round to the nearest hundredth. Use 3.14 for π.
- A. 2.4
- B. 207.64
- C. 15.1
- D. 30.1
Correct answer: B
Rationale: The formula for the area of a full circle is calculated as Area = π × (radius²). When finding the area of half a circle, we multiply by 0.5. Thus, the formula becomes Area = 0.5 × π × (radius²). Given that the radius of the circular garden is 11.5 feet, the calculation using π = 3.14 is as follows: Area = 0.5 × 3.14 × (11.5²) = 0.5 × 3.14 × 132.25 = 0.5 × 415.27 = 207.64 square feet. Therefore, the correct answer is B. Choices A, C, and D are incorrect because they do not reflect the correct calculation for finding the area of half a circular garden with a radius of 11.5 feet.
4. A set of patients is divided into groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Order the groups from smallest to largest.
- A. Alpha, Beta, Gamma
- B. Alpha, Gamma, Beta
- C. Gamma, Alpha, Beta
- D. Gamma, Beta, Alpha
Correct answer: C
Rationale: To determine the order from smallest to largest groups, we look at the fractions representing the groups. Group Gamma has 1/6, which is the smallest fraction, followed by Group Alpha with 1/2, and Group Beta with 1/3 being the largest fraction. So, the correct order is Gamma, Alpha, Beta. Choice A is incorrect because it lists Alpha, Beta, Gamma, which is the reverse order. Choice B is incorrect as it lists Alpha, Gamma, Beta, which is also incorrect. Choice D is incorrect as it lists Gamma, Beta, Alpha, which is not the correct order based on the fractions provided.
5. During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?
- A. 15 shifts
- B. 14 shifts
- C. 16 shifts
- D. 17 shifts
Correct answer: B
Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).
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