Nursing Elites

1. Simplify the following expression: 5/9 × 15/36

• A. 5/36
• B. 8/27
• C. 10/17
• D. 15/27

Correct answer: A

Rationale: To simplify the given expression, multiply the numerators together and the denominators together. 5/9 × 15/36 = (5 × 15) / (9 × 36) = 75 / 324. Now, simplify the resulting fraction by finding the greatest common divisor (GCD) of 75 and 324, which is 3. Divide both the numerator and denominator by 3 to get the simplified fraction: 75 ÷ 3 / 324 ÷ 3 = 25 / 108. Therefore, the simplified form of 5/9 × 15/36 is 25/108, which is equivalent to 5/36. Choice A, 5/36, is the correct answer. Choice B, 8/27, is incorrect as it does not match the simplified form of the expression. Choice C, 10/17, is unrelated and does not result from the given multiplication. Choice D, 15/27, does not correspond to the simplification of the given expression.

2. In a fraction, which number is the numerator and which is the denominator?

• A. Numerator: top, Denominator: bottom
• B. Numerator: bottom, Denominator: top
• C. Numerator: left, Denominator: right
• D. Numerator: right, Denominator: left

Correct answer: A

Rationale: The correct answer is A: 'Numerator: top, Denominator: bottom.' In a fraction, the numerator is the top number, representing the part of the whole being considered, while the denominator is the bottom number, indicating the total number of equal parts into which the whole is divided. Choices B, C, and D are incorrect because they provide inaccurate descriptions of the numerator and denominator positions in a fraction.

3. A person drives 300 miles at 60 mph, then another 200 miles at 80 mph, with a 30-minute break. How long does the trip take?

• A. 5.5 hours
• B. 7 hours
• C. 6 hours
• D. 4.5 hours

Correct answer: C

Rationale: To find the total time, we calculate the time taken for each segment: 300 miles at 60 mph = 300 miles ÷ 60 mph = 5 hours; 200 miles at 80 mph = 200 miles ÷ 80 mph = 2.5 hours. Adding these gives 5 hours + 2.5 hours = 7.5 hours. Converting the 30-minute break to hours (30 minutes ÷ 60 = 0.5 hours), the total time taken is 7.5 hours + 0.5 hours = 8 hours. Therefore, the correct answer is not among the given choices. The rationale provided in the original question is incorrect as it does not account for the break time and has a calculation error in adding the individual times.

4. The force applied is directly proportional to the stretch of a coil. If a force of 132 Newtons stretches a coil 0.07 meters, what force would be needed to stretch a coil 0.1 meter? Round your answer to the nearest tenth.

• A. 92.4 Newtons
• B. 1885.7 Newtons
• C. 188.6 Newtons
• D. 136.0 Newtons

Correct answer: C

Rationale: To find the force needed to stretch the coil 0.1 meters, we can set up a proportion based on the given information. The initial force and stretch are in direct proportion, so we can use this relationship to determine the unknown force. (132 N / 0.07 m) = X / 0.1 m. Cross-multiplying, we get 132 N * 0.1 m / 0.07 m = 188.57 N, which rounds to 188.6 N. Therefore, the correct answer is 188.6 Newtons. Choice A is incorrect as it does not match the calculated answer. Choice B is significantly higher and does not align with the proportional relationship. Choice D is close but does not account for the correct rounding as specified in the question.

5. How many whole boxes measuring 2 ft * 2 ft * 2 ft can be stored in a room measuring 9 ft * 9 ft * 9 ft, without altering the box size?

• A. 125
• B. 64
• C. 18
• D. 92

Correct answer: D

Rationale: The total volume of the room is 729 ft³ (9 ft * 9 ft * 9 ft). Each box has a volume of 8 ft³ (2 ft * 2 ft * 2 ft). Dividing the room's volume by the box volume, we get 729 ft³ / 8 ft³ ≈ 91.125. Since we can't have a fraction of a box, the maximum number of whole boxes that can fit is 92. Therefore, the correct answer is 92. Choice A (125) is incorrect as it does not result from the correct calculation. Choice B (64) and Choice C (18) are also incorrect and do not accurately represent the number of boxes that can fit in the room based on the given dimensions.

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