Nursing Elites

1. Alan currently weighs 200 pounds, but he wants to lose weight to get down to 175 pounds. What is the difference in kilograms? (1 pound is approximately equal to 0.45 kilograms.)

• A. 9 kg
• B. 11.25 kg
• C. 78.75 kg
• D. 90 kg

Correct answer: B

Rationale: The difference between Alan's current weight of 200 pounds and his goal weight of 175 pounds is 25 pounds (200 pounds - 175 pounds). To convert pounds to kilograms, you multiply the number of pounds by 0.45 (not divide by 2.2). Thus, 25 pounds is approximately 11.25 kilograms (25 pounds x 0.45). Therefore, the difference in kilograms is 11.25 kg. Choice A is incorrect because it miscalculates the conversion. Choices C and D are significantly higher values and do not reflect the correct conversion from pounds to kilograms.

2. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

3. What is the value of b in this equation? 5b - 4 = 2b + 17

• A. 13
• B. 24
• C. 7
• D. 21

Correct answer: C

Rationale: To find the value of b in the equation 5b - 4 = 2b + 17, you need to first simplify the equation. By subtracting 2b from both sides of the equation and adding 4 to both sides, you get 3b = 21. Then, dividing both sides of the equation by 3 gives you b = 7. Therefore, the value of b is 7, which corresponds to option C. Choice A (13) is incorrect as it does not match the correct calculation. Choice B (24) is incorrect as it is not the result of the correct algebraic manipulation. Choice D (21) is incorrect as it is not the value of b obtained after solving the equation step by step.

4. The table below shows the number of books checked out from a library over the course of 4 weeks. Which equation describes the relationship between the number of books (b) and weeks (w)?

• A. b = 10w + 2
• B. b = 5w + 10
• C. b = 8w + 12
• D. b = 4w + 20

Correct answer: B

Rationale: The relationship between the number of books and weeks is best described by the equation b = 5w + 10. This is because the initial value of books checked out is 10, which indicates that even with 0 weeks, there are already 10 books checked out. The rate at which books are checked out per week is 5, as indicated by the coefficient of w. Therefore, the correct equation should be b = 5w + 10. Choices A, C, and D are incorrect because they do not represent the correct initial value or rate of increase for the given scenario.

5. Over several years, a real estate agent sold houses, with one year having an outlier where she sold 11 houses. Which of the following measures will most accurately reflect the number of houses she sold per year?

• A. mean
• B. median
• C. mode
• D. range

Correct answer: B

Rationale: The outlier of 11 would skew the data if the mean or range were used. The median, however, is not affected by outliers and is the most appropriate measure for reflecting the number of houses she sold per year. In this scenario, the data set does not have a mode as each value occurs only once, making mode not the most appropriate choice.

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