Nursing Elites

1. A study about anorexia was conducted on 100 patients. 70% were women, and 10% of the men were overweight as children. How many male patients were not overweight as children?

• A. 3
• B. 10
• C. 27
• D. 30

Correct answer: C

Rationale: Out of the 100 patients, 30% were men, which equals 30 male patients. It is given that 10% of the men were overweight as children, so 10% of 30 is 3, meaning 3 male patients were overweight. Therefore, the remaining 27 male patients were not overweight as children. Choice A, B, and D are incorrect as they do not accurately represent the number of male patients who were not overweight.

2. A mathematics test has a 4:2 ratio of data analysis problems to algebra problems. If the test has 18 algebra problems, how many data analysis problems are on the test?

• A. 24
• B. 28
• C. 36
• D. 38

Correct answer: C

Rationale: The ratio of 4:2 simplifies to 2:1. This means that for every 2 algebra problems, there is 1 data analysis problem. If there are 18 algebra problems, we can set up a proportion: 2 algebra problems correspond to 1 data analysis problem. Therefore, 18 algebra problems correspond to x data analysis problems. Solving the proportion, x = 18 * 1 / 2 = 9. Hence, there are 9 data analysis problems on the test. Therefore, the total number of data analysis problems on the test is 18 (algebra problems) + 9 (data analysis problems) = 27.

3. Solve for x: 3(x - 1) = 2(3x - 9)

• A. x = 2
• B. x = 8/3
• C. x = -5
• D. x = 5

Correct answer: D

Rationale: To solve the equation 3(x - 1) = 2(3x - 9), first distribute and simplify both sides to get 3x - 3 = 6x - 18. Next, subtract 3x from both sides to get -3 = 3x - 18. Then, add 18 to both sides to obtain 15 = 3x. Finally, divide by 3 to find x = 5. Therefore, the correct answer is x = 5. Choices A, B, and C are incorrect because they do not represent the correct solution to the given equation after proper algebraic manipulation.

4. A study was conducted where patients were divided into three groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Which group is the smallest?

• A. Group Alpha
• B. Group Beta
• C. Group Gamma
• D. Group Gamma

Correct answer: C

Rationale: The smallest group is Group Gamma, which had 1/6 of the total number of patients. To determine the smallest group, compare the fractions representing the portions of patients in each group. 1/6 is smaller than 1/3 and 1/2, making Group Gamma the smallest. Group Alpha and Group Beta have larger fractions of patients, making them larger groups compared to Group Gamma.

5. Veronica has to create the holiday schedule for the neonatal unit at her hospital. 35% of her staff will be unavailable during the holidays, and of the remaining staff, only 20% are certified to work in the neonatal unit. What percentage of the total staff is certified and available to work?

• A. 7%
• B. 13%
• C. 65%
• D. 80%

Correct answer: B

Rationale: The correct answer is 13%. To find the percentage of the total staff that is certified and available to work, we first calculate the percentage of staff available, which is 100% - 35% = 65%. Then, we find the percentage of the available staff that is certified, which is 20% of 65% = 0.20 × 0.65 = 0.13, or 13%.

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