ATI TEAS 7
TEAS Practice Test Math
1. In a class of 48 students, there are 22 boys and 26 girls. What is the ratio of girls to boys in the class?
- A. 26:11
- B. 13:11
- C. 13:22
- D. 11:13
Correct answer: B
Rationale: To find the ratio of girls to boys, divide the number of girls by the number of boys: 26/22 = 13/11. Therefore, the correct ratio is 13:11. Choice A is incorrect as it includes an extra '00'. Choice C is incorrect as it reverses the order of girls to boys. Choice D is incorrect as it reverses the order and provides the ratio of boys to girls.
2. Bridget is repainting her rectangular bedroom. Two walls measure 15 feet by 9 feet, and the other two measure 12.5 feet by 9 feet. One gallon of paint covers an average of 32 square meters. Which of the following is the number of gallons of paint that Bridget will use? (There are 3.28 feet in 1 meter.)
- A. 0.72 gallons
- B. 1.43 gallons
- C. 4.72 gallons
- D. 15.5 gallons
Correct answer: B
Rationale: First, convert the dimensions to meters: 15 ft. × (1 m/3.28 ft.) = 4.57 m; 9 ft. × (1 m/3.28 ft.) = 2.74 m; 12.5 ft. × (1 m/3.28 ft.) = 3.81 m. Next, find the total area in square meters: total area = 2(4.57 m × 2.74 m) + 2(3.81 m × 2.74 m) = 45.9 m². Finally, convert the area to gallons of paint: 45.9 m² × (1 gallon/32 m²) = 1.43 gallons. Therefore, Bridget will need 1.43 gallons of paint to repaint her bedroom. Choices A, C, and D are incorrect because they do not accurately calculate the required amount of paint based on the given dimensions and the coverage area of one gallon of paint.
3. What is the least common denominator of two fractions?
- A. The smallest number that is a multiple of both denominators
- B. The smallest number that both fractions can divide into evenly
- C. The least common multiple of both denominators
- D. The greatest common factor of both denominators
Correct answer: C
Rationale: The least common denominator of two fractions is the least common multiple of both denominators. This is because the least common denominator is the smallest number that both denominators can divide into evenly, ensuring that both fractions can be expressed with a common denominator. Choice A is incorrect as the least common denominator is a multiple of both denominators, not a number that multiplies into both. Choice B is incorrect because the common denominator needs to be a multiple of both denominators, not just a number they can divide into evenly. Choice D is incorrect as the greatest common factor is not used to find the least common denominator, but rather the least common multiple.
4. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?
- A. shifts = 20 + 3 + 1/2
- B. shifts = (20)(3)(1/2)
- C. shifts = (20)(3) + 1/2
- D. shifts = 20 + (3)(1/2)
Correct answer: B
Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.
5. The length of a rectangle is 3 units greater than its width. Which expression correctly represents the perimeter of the rectangle?
- A. 2W + 2(W + 3)
- B. W + W + 3
- C. W(W + 3)
- D. 2W + 2(3W)
Correct answer: A
Rationale: To find the perimeter of a rectangle, you add up all its sides. In this case, the length is 3 units greater than the width, so the length can be expressed as W + 3. The formula for the perimeter of a rectangle is 2W + 2(L), where L represents the length. Substituting W + 3 for L, the correct expression for the perimeter becomes 2W + 2(W + 3), which simplifies to 2W + 2W + 6 or 4W + 6. Choices B, C, and D do not correctly represent the formula for the perimeter of a rectangle. Choice B simply adds the width twice to 3, neglecting the length. Choice C multiplies the width by the sum of the width and 3, which is incorrect. Choice D combines the width and 3 times the width, which is not the correct formula for the perimeter of a rectangle.
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