ATI TEAS 7
TEAS Exam Math Practice
1. A circular swimming pool has a circumference of 49 feet. What is the diameter of the pool?
- A. 15.6 feet
- B. 17.8 feet
- C. 49 feet
- D. 153.9 feet
Correct answer: A
Rationale: The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter. Given C = 49 feet, we can rearrange the formula to solve for d: 49 feet = πd. To find the diameter, we divide both sides by π, giving us d = 49 feet / π ≈ 15.6 feet. Therefore, the diameter of the swimming pool is approximately 15.6 feet. Choices B, C, and D are incorrect because they do not align with the calculation based on the formula for the circumference of a circle.
2. Simplify the expression. Which of the following is correct? (3/2)(8/3) ÷ (5/4)
- A. 1
- B. 2
- C. 3
- D. 4
Correct answer: B
Rationale: Using PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction): (3/2)(8/3) ÷ (5/4) = (24/6) ÷ (5/4) = (4/1) ÷ (5/4). To divide fractions, the second fraction is flipped and then multiplied by the first fraction, resulting in (4/1)(4/5) = (16/5), which simplifies to 3(1/5) or 2.
3. A rectangular solid box has a square base with a side length of 5 feet and a height of h feet. If the volume of the box is 200 cubic feet, which of the following equations can be used to find h?
- A. 5h = 200
- B. 5h² = 200
- C. 25h = 200
- D. h = 200 ÷ 5
Correct answer: C
Rationale: The volume formula for a rectangular solid is V = l × w × h. In this case, the length and width are both 5 feet. Substituting the values into the formula gives V = 5 × 5 × h = 25h = 200. Therefore, h = 200 ÷ 25 = 8. Option A is incorrect because the product of length, width, and height is not directly equal to the volume. Option B is incorrect as squaring the height is not part of the volume formula. Option D is incorrect as it oversimplifies the relationship between height and volume, not considering the base dimensions.
4. Bob decides to go into business selling lemonade. He buys a wooden stand for $45 and sets it up outside his house. He figures that the cost of lemons, sugar, and paper cups for each glass of lemonade sold will be 10¢. Which of these expressions describes his cost for making g glasses of lemonade?
- A. $45 + $0.1 × g
- B. $44.90 × g
- C. $44.90 × g + 10¢
- D. $90
Correct answer: A
Rationale: The cost for making g glasses of lemonade includes the initial cost of the stand ($45) plus 10¢ for each glass of lemonade sold. Therefore, the expression that represents the cost for making g glasses of lemonade is $45 + $0.1 × g, which matches option A. Choice B, $44.90 × g, is incorrect as it does not account for the initial stand cost of $45. Choice C, $44.90 × g + 10¢, is incorrect because it does not include the initial stand cost and incorrectly adds an extra 10¢ for every glass. Choice D, $90, is incorrect as it does not consider the variable cost of 10¢ per glass and only represents the initial stand cost.
5. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?
- A. Histogram
- B. Pie chart
- C. Bar graph
- D. Scatter plot
Correct answer: A
Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.
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