ATI TEAS 7
TEAS Math Questions
1. In a class of 30 students, with 60% boys and 40% girls, how many girls are in the class?
- A. 18 girls
- B. 12 girls
- C. 15 girls
- D. 10 girls
Correct answer: B
Rationale: To find the number of girls in the class, we need to calculate 40% of the total number of students, which is 30. 40% of 30 is 0.40 * 30 = 12 girls. Therefore, there are 12 girls in the class. Choice A, 18 girls, is incorrect as it miscalculates the percentage. Choice C, 15 girls, is incorrect as it misrepresents the correct calculation. Choice D, 10 girls, is incorrect as it underestimates the number of girls in the class.
2. Sarah works part-time and earns $12 per hour. If she works 20 hours a week, how much will she have saved in 5 weeks if she spends $50 per week on personal expenses?
- A. $600
- B. $750
- C. $500
- D. $650
Correct answer: C
Rationale: To find out how much Sarah saves in 5 weeks, first calculate her weekly earnings: $12/hour × 20 hours/week = $240/week. Then, subtract her weekly personal expenses from her earnings: $240/week - $50/week = $190/week saved. Over 5 weeks, she will save $190/week × 5 weeks = $950. However, none of the provided answer choices match $950. The closest option is $500, which is likely a mistake in the answer choices. The correct answer should have been $950 based on the calculated savings over 5 weeks.
3. Which of the following statements is true?
- A. The mean is less than the median
- B. The mode is greater than the median
- C. The mode is less than the mean, median, and range
- D. The mode is equal to the range
Correct answer: A
Rationale: The mean is the average of a set of numbers, while the median is the middle value when the numbers are arranged in order. If a set of numbers is skewed to one side with some outliers, the mean can be influenced by these extreme values, causing it to be greater or less than the median. In cases of skewed distribution, the mean typically shifts towards the direction of the outliers, making it less than the median. Choice B is incorrect because the mode, which is the most frequent number in a dataset, may or may not be greater than the median. Choice C is incorrect because the mode can be greater than the mean or median, depending on the data. Choice D is incorrect because the mode, representing the most frequent value, has no direct relationship with the range, which is the difference between the highest and lowest values in a dataset.
4. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?
- A. 3/12
- B. 3/55
- C. 2/10
- D. 1/3
Correct answer: B
Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.
5. A patient requires a 30% decrease in their medication dosage. Their current dosage is 340 mg. What will their dosage be after the decrease?
- A. 70 mg
- B. 238 mg
- C. 270 mg
- D. 340 mg
Correct answer: B
Rationale: To calculate a 30% decrease of 340 mg, multiply 340 by 0.30 to get 102. Subtracting 102 from 340 gives a new dosage of 238 mg. Choice A (70 mg) is incorrect as it represents a 80% decrease, not 30%. Choice C (270 mg) is incorrect as it does not reflect a decrease but rather the original dosage. Choice D (340 mg) is incorrect as it is the original dosage and not reduced by 30%.
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