Nursing Elites

1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

2. Which measure for the center of a small sample set would be most affected by outliers?

• A. Mean
• B. Median
• C. Mode
• D. None of the above

Correct answer: A

Rationale: The mean is calculated by summing all values in a dataset and then dividing by the total number of values. Outliers, which are data points significantly different from the other values, can greatly impact the mean because they affect the sum. The mean is sensitive to extreme values, making it the measure for the center of a small sample set most affected by outliers. The median, on the other hand, is not influenced by outliers as it represents the middle value when the data points are ordered. The mode is the value that appears most frequently in the dataset and is not directly influenced by outliers. Therefore, the correct answer is the mean, as it is highly influenced by outliers in a small sample set.

3. Which statement best describes the rate of change?

• A. Every day, the snow melts 10 centimeters.
• B. Every day, the snow melts 5 centimeters.
• C. Every day, the snow increases by 10 centimeters.
• D. Every day, the snow increases by 5 centimeters.

Correct answer: B

Rationale: The rate of change refers to how one quantity changes concerning another quantity. In this scenario, the rate of change is the amount of snow melting per day, which is 5 centimeters. This is determined by the slope of the graph, indicating a decrease in snow depth. Choices C and D incorrectly describe an increase in snow depth, while choice A exaggerates the rate of snow melting compared to the actual value of 5 centimeters per day.

4. The length of a rectangle is 3 times its width. If the width is 4 inches, what is the perimeter of the rectangle?

• A. 28 inches
• B. 24 inches
• C. 30 inches
• D. 32 inches

Correct answer: A

Rationale: To find the perimeter of a rectangle, you add up all its sides. Given that the width is 4 inches and the length is 3 times the width (3 * 4 = 12 inches), the perimeter formula is 2 * (length + width). Substituting the values, we get 2 * (12 + 4) = 2 * 16 = 32 inches. Therefore, the correct answer is 32 inches. Choices B, C, and A are incorrect because they do not reflect the correct calculation of the rectangle's perimeter.

5. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

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