a charter bus driver drove at an average speed of 65 mph for 305 miles if he stops at a gas station for 15 minutes then drives another 162 miles at an

ATI TEAS 7

ATI TEAS Math Practice Test

1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

A. 0.96 hours
B. 6.44 hours
C. 6.69 hours
D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

2. Solve the following: 4 x 7 + (25 – 21)²

A. 512
B. 36
C. 44
D. 22

Correct answer: B

Rationale: First, solve the expression inside the parentheses: 25 − 21 = 4 25−21=4 Then, square the result from the parentheses: 4 2 = 16 4 2 =16 Perform the multiplication: 4 × 7 = 28 4×7=28 Finally, add the results: 28 + 16 = 44 28+16=44

3. Which of the following numbers is the largest?

A. 0.45
B. 0.096
C. 0.3
D. 0.313

Correct answer: A

Rationale: Among the provided options, 0.45 is the largest number. To determine the largest number, compare the decimal values directly. 0.45 is greater than 0.313, 0.3, and 0.096. Therefore, 0.45 is the correct answer. Choice B (0.096) is the smallest as it has the lowest decimal value. Choice C (0.3) is greater than 0.096 but smaller than both 0.313 and 0.45. Choice D (0.313) is greater than 0.3 and 0.096 but smaller than 0.45, making it incorrect.

4. How will the number 847.89632 be written if rounded to the nearest hundredth?

A. 847.90
B. 900
C. 847.89
D. 847.896

Correct answer: A

Rationale: When rounding to the nearest hundredth, we look at the digit in the thousandth place, which is 8. Since the next digit, in the ten-thousandth place, is 9 (greater than or equal to 5), we round up the hundredth place digit. Therefore, 847.89632 rounded to the nearest hundredth is 847.90. Choice B (900) is incorrect as it does not round the number to the nearest hundredth. Choice C (847.89) is also incorrect as it drops the digit 6 in the ten-thousandth place. Choice D (847.896) does not round the number to the nearest hundredth as it retains the thousandth place digit 3.

5. A gift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?

A. 56
B. 244
C. 488
D. 672

Correct answer: C

Rationale: To find the surface area of a rectangular prism, you use the formula SA = 2lw + 2wh + 2hl, where l is the length, w is the width, and h is the height. Substituting the given dimensions, the calculation would be SA = 2(14)(6) + 2(6)(8) + 2(8)(14) = 168 + 96 + 224 = 488 square inches. Therefore, 488 square inches of wrapping paper are needed to wrap the box. Choice A (56), Choice B (244), and Choice D (672) are incorrect because they do not represent the correct surface area calculation for the given box dimensions.