ATI TEAS 7
ATI TEAS Math Practice Test
1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?
- A. 0.96 hours
- B. 6.44 hours
- C. 6.69 hours
- D. 6.97 hours
Correct answer: D
Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.
2. Four people split a bill. The first person pays for 1/3, the second person pays for 1/4, and the third person pays for 1/6. What fraction of the bill does the fourth person pay?
- A. 1/4
- B. 1/6
- C. 1/3
- D. 1/12
Correct answer: D
Rationale: To find out what fraction of the bill the fourth person pays, you first calculate the total fraction paid by the first three people: 1/3 + 1/4 + 1/6 = 4/12 + 3/12 + 2/12 = 9/12 = 3/4. This means that the first three people paid 3/4 of the bill. Therefore, the fourth person pays the remaining fraction: 1 - 3/4 = 1/4. So, the fourth person pays 1/4 of the bill. Choice A, 1/4, is incorrect because this is the total fraction paid by the first person. Choice B, 1/6, is incorrect as this is the fraction paid by the second person. Choice C, 1/3, is incorrect as this is the fraction paid by the third person.
3. Which of the following is the correct solution to the equation 3x + 4 = 19?
- A. x = 3
- B. x = 4
- C. x = 5
- D. x = 6
Correct answer: C
Rationale: To solve the equation 3x + 4 = 19, first, subtract 4 from both sides to isolate the term with x, which gives 3x = 15. Then, divide both sides by 3 to solve for x, resulting in x = 5. Therefore, the correct answer is x = 5. Choice A, x = 3, is incorrect as it does not satisfy the equation. Choice B, x = 4, is also incorrect as it does not make the equation true. Choice D, x = 6, is incorrect as it does not align with the correct solution obtained through the proper algebraic steps.
4. Simplify the expression. Which of the following is the value of x? (5(4x – 5) = (3/2)(2x – 6))
- A. −(2/7)
- B. −(4/17)
- C. (16/17)
- D. (8/7)
Correct answer: C
Rationale: To solve the given proportion 5(4x – 5) = (3/2)(2x – 6), first distribute to get 20x - 25 = 3x - 9. Then, simplify the linear equation by isolating x: 20x - 3x = 25 - 9, which leads to 17x = 16. Finally, solving for x gives x = 16/17. Choice A is incorrect as it does not match the calculated value of x. Choice B is incorrect as it does not correspond to the correct solution for x. Choice D is incorrect as it does not align with the accurate value of x obtained from solving the equation.
5. Simplify the expression: 2x + 3x - 5.
- A. 5x - 5
- B. 5x
- C. x - 5
- D. 2x - 5
Correct answer: A
Rationale: To simplify the expression 2𝑥 + 3𝑥 - 5, follow these steps: Identify and combine like terms. The terms 2𝑥 and 3𝑥 are both 'like terms' because they both contain the variable 𝑥. Add the coefficients of the like terms: 2𝑥 + 3𝑥 = 5𝑥. Simplify the expression. After combining the like terms, the expression becomes 5𝑥 - 5, which includes the simplified term 5𝑥 and the constant -5. Thus, the fully simplified expression is 5𝑥 - 5, making Option A the correct answer. This method ensures all terms are correctly simplified by combining similar elements and retaining constants.
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