a charter bus driver drove at an average speed of 65 mph for 305 miles if he stops at a gas station for 15 minutes then drives another 162 miles at an
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ATI TEAS 7

ATI TEAS Math Practice Test

1. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

2. If the population of a city increases by 5% annually, what will the population be next year if the current population is 1,000?

Correct answer: A

Rationale: To calculate the population increase, multiply the current population by 1 plus the percentage increase. So, 1,000 * 1.05 = 1,050 people. Therefore, the correct answer is A. Choice B (1,200 people) is incorrect because it represents a 20% increase from the current population, not 5%. Choice C (1,100 people) is incorrect as it reflects a 10% increase, not a 5% increase. Choice D (1,300 people) is incorrect, showing a 30% increase, which is not the scenario given.

3. Solve the inequality for the unknown.

Correct answer: A

Rationale: When solving an inequality, the direction of the inequality sign changes depending on the operation performed. In this case, if the given inequality simplifies to x > 5, it means that the unknown value x must be greater than 5 for the inequality to hold true. Therefore, x > 5 is the correct solution. Option A is correct. Choices B, C, and D are incorrect because they do not correctly represent the relationship between x and 5 based on the given inequality.

4. Which of the following equations correctly models the relationship between x and y when y is three times x?

Correct answer: A

Rationale: The correct equation that models the relationship between x and y when y is three times x is y = 3x. This equation represents that y is equal to three times x. Choice B (x = 3y) incorrectly reverses the relationship, stating that x is equal to three times y. Choice C (y = x + 3) and Choice D (y = x / 3) do not correctly represent a relationship where y is three times x, making them incorrect choices.

5. The length of a rectangle is 3 units greater than its width. Which expression correctly represents the perimeter of the rectangle?

Correct answer: A

Rationale: To find the perimeter of a rectangle, you add up all its sides. In this case, the length is 3 units greater than the width, so the length can be expressed as W + 3. The formula for the perimeter of a rectangle is 2W + 2(L), where L represents the length. Substituting W + 3 for L, the correct expression for the perimeter becomes 2W + 2(W + 3), which simplifies to 2W + 2W + 6 or 4W + 6. Choices B, C, and D do not correctly represent the formula for the perimeter of a rectangle. Choice B simply adds the width twice to 3, neglecting the length. Choice C multiplies the width by the sum of the width and 3, which is incorrect. Choice D combines the width and 3 times the width, which is not the correct formula for the perimeter of a rectangle.

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