Nursing Elites

1. Jerry needs to load four pieces of equipment onto a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would be the average weight of each item so that the elevator's weight limit is not exceeded?

• A. 128 pounds
• B. 150 pounds
• C. 175 pounds
• D. 180 pounds

Correct answer: B

Rationale: To find the average weight per item, subtract Jerry's weight from the elevator's weight limit: 800 - 200 = 600 pounds. Since there are 4 items, divide 600 by 4 to determine that each item should weigh 150 pounds. Choice A (128 pounds), C (175 pounds), and D (180 pounds) are incorrect as they do not correctly calculate the average weight per item to ensure the elevator's weight limit is not exceeded.

2. A cell has a diameter of 0.1 meter, and another cell has a diameter of 0.05 meters. How many times larger is the first cell compared to the second cell?

• A. 2
• B. 4
• C. 8
• D. 16

Correct answer: A

Rationale: To determine how many times larger the first cell is compared to the second cell, divide the diameter of the first cell by the diameter of the second cell: 0.1 / 0.05 = 2. Therefore, the first cell is 2 times larger than the second cell. Choice B, C, and D are incorrect because they do not provide the accurate calculation for the size difference between the two cells.

3. Which of the following describes a proportional relationship?

• A. Johnathan opens a savings account with an initial deposit of $150 and deposits $125 per month
• B. Bruce pays his employees $12 per hour worked during the month of December, as well as a $250 bonus
• C. Alvin pays $28 per month for his phone service plus $0.07 for each long-distance minute used
• D. Kevin drives 65 miles per hour

Correct answer: A

Rationale: A proportional relationship is one in which two quantities vary directly with each other. In choice A, the amount deposited per month is directly proportional to the initial deposit. The relationship can be represented as y = 125x + 150, where x is the number of months and y is the total amount in the account. Choices B and C involve additional fixed amounts or variable costs that do not maintain a constant ratio, making them non-proportional relationships. Choice D refers to a constant speed of driving, which is not a proportional relationship as it does not involve varying quantities that change in direct proportion.

4. A farmer had about 150 bags of potatoes on his trailer. Each bag contained from 23 to 27 pounds of potatoes. What is the best estimate of the total number of pounds of potatoes on the farmer’s trailer?

• A. 3,000 pounds
• B. 3,700 pounds
• C. 4,100 pounds
• D. 5,000 pounds

Correct answer: B

Rationale: To estimate the total number of pounds of potatoes on the farmer's trailer, we can use the average weight of a bag of potatoes. The average weight is calculated by adding the minimum and maximum weights of the bags and dividing by 2: (23 + 27) / 2 = 25 pounds. Next, multiply the average weight by the total number of bags: 25 pounds/bag * 150 bags = 3,750 pounds. Therefore, the best estimate of the total number of pounds of potatoes on the farmer's trailer is 3,750 pounds. Choice A (3,000 pounds) is too low as it underestimates the total weight. Choice C (4,100 pounds) and Choice D (5,000 pounds) are too high as they overestimate the total weight.

5. If 1 inch on a map represents 60 ft, how many yards apart are two points if the distance between the points on the map is 10 inches?

• A. 1800
• B. 600
• C. 200
• D. 2

Correct answer: B

Rationale: If 1 inch on the map represents 60 ft, then for 10 inches on the map, the actual distance would be 10 inches x 60 ft = 600 ft. To convert this to yards, we know that 1 yard equals 3 feet. Therefore, the distance between the two points is 600 ft / 3 ft/yard = 200 yards. Choice A (1800) is incorrect because it incorrectly multiplies by 10 again instead of converting to yards. Choice C (200) is incorrect because it fails to adjust the measurement from feet to yards. Choice D (2) is incorrect as it does not consider the correct conversion factor from feet to yards.

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