Nursing Elites

1. Which type of orbital can hold a maximum of 10 electrons?

• A. s orbital
• B. p orbital
• C. d orbital
• D. f orbital

Correct answer: D

Rationale: The correct answer is the f orbital. Each f orbital can hold up to 2 electrons. Since there are 5 f orbitals, the total maximum number of electrons that can be accommodated in f orbitals is 10 (2 electrons per orbital x 5 orbitals = 10 electrons). Therefore, the f orbital can hold a maximum of 10 electrons. Choice A, s orbital, is incorrect because it can hold a maximum of 2 electrons. Choice B, p orbital, is incorrect because it can hold a maximum of 6 electrons (3 orbitals x 2 electrons per orbital = 6 electrons). Choice C, d orbital, is incorrect as it can hold a maximum of 10 electrons (5 orbitals x 2 electrons per orbital = 10 electrons), but the question asks for the type of orbital that can hold a maximum of 10 electrons, not the total number of electrons in d orbitals.

2. What cellular process ensures the accurate transmission of genetic material during cell division?

• A. Mitosis (somatic cell division)
• B. Meiosis (germ cell division)
• C. Replication (DNA duplication)
• D. Transcription (DNA to RNA conversion)

Correct answer: A

Rationale: Mitosis is the correct answer. Mitosis is the process by which somatic cells divide to produce two identical daughter cells. During mitosis, the genetic material is accurately replicated and distributed to ensure each daughter cell receives a complete set of chromosomes. This process is crucial for growth, repair, and maintenance of multicellular organisms. Meiosis, on the other hand, is the type of cell division that occurs in germ cells to produce gametes (sperm and egg cells), focusing on genetic diversity through recombination and reduction of chromosome number. Replication is the process of copying DNA to produce an identical copy, essential for cell division but not the specific process ensuring accurate genetic material transmission. Transcription involves copying DNA into RNA, crucial for gene expression but not directly related to the accurate transmission of genetic material during cell division.

3. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

4. Which neuromuscular system controls voluntary movement?

• A. Autonomic
• B. Somatic
• C. Sympathetic
• D. Parasympathetic

Correct answer: B

Rationale: The correct answer is B, Somatic. The somatic nervous system controls voluntary movements of skeletal muscles. It is responsible for carrying sensory and motor information to and from the central nervous system. Choices A, C, and D are incorrect. The autonomic nervous system (choice A) controls involuntary functions such as heart rate and digestion. The sympathetic (choice C) and parasympathetic (choice D) nervous systems are subdivisions of the autonomic nervous system and are responsible for the body's fight-or-flight response and rest-and-digest functions, respectively.

5. According to the wave theory of light, the bright fringes observed in a double-slit experiment correspond to:

• A. Constructive interference
• B. Destructive interference
• C. Increased diffraction
• D. Total internal reflection

Correct answer: A

Rationale: In a double-slit experiment based on the wave theory of light, the bright fringes are the result of constructive interference. Constructive interference occurs when light waves from the two slits arrive at a point in phase, reinforcing each other and creating a bright fringe. This reinforcement leads to the constructive addition of the wave amplitudes, resulting in a bright spot on the screen. Destructive interference, which would result in dark fringes, occurs when waves are out of phase and cancel each other out. Increased diffraction and total internal reflection are not related to the formation of bright fringes in a double-slit experiment. Therefore, the correct answer is constructive interference.

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