ATI TEAS 7
Mometrix TEAS 7 science practice test
1. Which term describes the resistance of a substance to flow?
- A. Density
- B. Viscosity
- C. Conductivity
- D. Malleability
Correct answer: B
Rationale: Viscosity is the term used to describe the resistance of a substance to flow. It quantifies how thick or thin a fluid is and how easily it flows. Density (A) refers to the mass of a substance per unit volume and does not directly relate to resistance to flow. Conductivity (C) is the property of a material to conduct electricity or heat, not related to resistance to flow. Malleability (D) is the property of a material to be hammered or rolled into thin sheets, which is not related to resistance to flow.
2. Which of the following structures can serve as a passageway for both food and air?
- A. Esophagus
- B. Laryngopharynx
- C. Nasopharynx
- D. Trachea
Correct answer: B
Rationale: The correct answer is the Laryngopharynx. It is a common passageway for both food and air. The Esophagus (Choice A) is solely for transporting food from the throat to the stomach. The Nasopharynx (Choice C) is primarily involved in the passage of air. The Trachea (Choice D) is responsible for conducting air to and from the lungs and does not play a role in the passage of food.
3. Where is pseudostratified columnar epithelium primarily found?
- A. Skeletal muscle
- B. Bony skeleton
- C. External ears
- D. Bloodstream
Correct answer: C
Rationale: Pseudostratified columnar epithelium is a type of epithelial tissue found in the respiratory tract, including the lining of the trachea and bronchi. It is also found in the male reproductive system and parts of the auditory tube and external ear canal. Among the options provided, the external ears (option C) are the most relevant location for pseudostratified columnar epithelium. Skeletal muscle (option A) is primarily composed of muscle fibers, not epithelial tissue. The bony skeleton (option B) is composed of bone tissue. The bloodstream (option D) consists of blood cells and plasma, not epithelial tissue.
4. What does the term 'electron configuration' refer to in relation to an atom?
- A. The arrangement of electrons in an atom's orbitals.
- B. The number of protons in an atom's nucleus.
- C. The number of neutrons in an atom's nucleus.
- D. The number of electrons in an atom's valence shell.
Correct answer: A
Rationale: The electron configuration of an atom refers to the arrangement of electrons in the atom's orbitals. This arrangement determines the atom's chemical properties and behavior. The number of protons in an atom's nucleus (option B) is known as the atomic number, which defines the element. The number of neutrons in an atom's nucleus (option C) contributes to the atom's mass number. The number of electrons in an atom's valence shell (option D) is important for understanding the atom's reactivity and bonding behavior, but the electron configuration specifically refers to how electrons are distributed among the different orbitals in an atom.
5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.
- A. 18.3 g
- B. 19.7 g
- C. 21.0 g
- D. 24.2 g
Correct answer: B
Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.
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