Nursing Elites

1. Which phenomenon describes the separation of light into its component colors when passing through a prism?

• A. Refraction
• B. Diffraction
• C. Dispersion
• D. Reflection

Correct answer: C

Rationale: Dispersion is the phenomenon that describes the separation of light into its component colors when passing through a prism. When white light enters a prism, it is refracted at different angles depending on its wavelength, causing the colors to spread out. Refraction is the bending of light as it passes from one medium to another, not the separation of colors. Diffraction is the bending of light around obstacles, not the separation of colors. Reflection is the bouncing back of light rays from a surface, not the separation of colors. In the context of a prism, dispersion plays a key role in the creation of a spectrum of colors by separating the different wavelengths present in white light.

2. Which type of tissue connects muscles to bones?

• A. Ligaments
• B. Tendons
• C. Cartilage
• D. Muscles

Correct answer: B

Rationale: The correct answer is B: Tendons. Tendons connect muscles to bones, not bones to muscles. They play a crucial role in transmitting the force generated by muscles to move bones, enabling movement. Ligaments (choice A) connect bones to bones, providing stability to joints. Cartilage (choice C) is a connective tissue found in joints, providing cushioning and flexibility. Muscles (choice D) are responsible for generating force through contraction but do not directly connect muscles to bones.

3. Where is the scapula in relation to the olecranon?

• A. Distal
• B. Lateral
• C. Ventral
• D. Superior

Correct answer: D

Rationale: The correct answer is D: 'Superior.' The scapula is located superior to the olecranon. In anatomical terms, 'superior' refers to a position above or higher than a reference point. 'Distal' is a term used to describe a position farther away from the point of attachment or origin. 'Lateral' refers to a position further away from the midline of the body. 'Ventral' refers to the front or anterior side of the body. In this case, the scapula being superior to the olecranon means it is positioned above the olecranon bone.

4. When sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), the resulting product is:

• A. Hydrogen gas and sodium chloride (NaCl)
• B. Chlorine gas and sodium oxide (Na2O)
• C. Sodium metal (Na) and water (H2O)
• D. No reaction occurs.

Correct answer: A

Rationale: When sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), a neutralization reaction occurs. The products of this reaction are water (H2O) and a salt, which is sodium chloride (NaCl). The chemical equation for this reaction is: NaOH + HCl -> NaCl + H2O. Choice B is incorrect because chlorine gas and sodium oxide are not the products of this reaction. Choice C is incorrect as sodium metal and water are not the products formed in this neutralization reaction. Choice D is incorrect because a reaction does occur between NaOH and HCl, resulting in the formation of NaCl and H2O. Therefore, the correct answer is A: Hydrogen gas and sodium chloride (NaCl).

5. How many moles of water are produced when 0.5 moles of methane (CH4) react with excess oxygen?

• A. 0.5 moles
• B. 1 mole
• C. 2 moles
• D. 3 moles

Correct answer: B

Rationale: The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O. This equation shows that 1 mole of methane produces 2 moles of water. Therefore, when 0.5 moles of methane react, they will produce 1 mole of water. The ratio of water to methane is 2:1, meaning that for every mole of methane that reacts, it produces 2 moles of water. Since only 0.5 moles of methane are reacting, the amount of water produced will be half of what would be produced if 1 mole of methane reacted, resulting in 1 mole of water being produced. Choice A is incorrect because it does not consider the stoichiometry of the reaction. Choices C and D are incorrect as they do not align with the balanced chemical equation and the stoichiometric ratios involved in the reaction.

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