ATI TEAS 7
TEAS Exam Math Practice
1. Which of the following lists is in order from least to greatest? 2−1 , −(4/3), (−1)3 , (2/5)
- A. 2−1 , −(4/3), (−1)3 , (2/5)
- B. −(4/3), (−1)3 , 2−1 , (2/5)
- C. −(4/3), (2/5), 2−1 , (−1)3
- D. −(4/3), (−1)3 , (2/5), 2−1
Correct answer: D
Rationale: To determine the correct order from least to greatest, start by simplifying the expressions. 2^(-1) = 1/2 and (-1)^3 = -1. Now, comparing the values, (-4/3) is the most negative, followed by -1, then (2/5), and finally 1/2. Therefore, the correct order is (-4/3), (-1)^3, (2/5), 2^(-1), making choice D the correct answer. Choices A, B, and C are incorrect because they do not follow the correct order from least to greatest as determined by comparing the values of the expressions after simplification.
2. Two even integers and one odd integer are multiplied together. Which of the following could be their product?
- A. 3.75
- B. 9
- C. 16.2
- D. 24
Correct answer: D
Rationale: When multiplying two even integers and one odd integer, the product will always be even. This is because multiplying any number of even integers will always result in an even number. Therefore, the only possible product from the given options is 24, as it is the only even number listed. Choices A, B, and C are incorrect as they are all odd numbers, and the product of two even integers and one odd integer will never result in an odd number.
3. A recipe calls for 5.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?
- A. 10.2 mL
- B. 12 mL
- C. 7.43 mL
- D. 27 mL
Correct answer: D
Rationale: To convert the amount of vanilla from teaspoons to milliliters, we multiply the number of teaspoons by the conversion factor of 4.93 mL/teaspoon. 5.5 teaspoons * 4.93 mL/teaspoon = 27.115 mL, which rounds to 27 mL. Therefore, the correct amount of vanilla in mL is 27 mL. Choice A (10.2 mL), Choice B (12 mL), and Choice C (7.43 mL) are incorrect as they do not correctly convert the given amount of teaspoons to milliliters based on the provided conversion factor.
4. Histograms use ________, and bar graphs do not.
- A. Ranges
- B. Categories
- C. Labels
- D. Percentages
Correct answer: A
Rationale: Correct Answer: Ranges. Histograms utilize ranges (intervals) to display the frequency distribution of continuous data, highlighting the frequency of values falling within each interval. Bar graphs, on the other hand, represent discrete data using separate and distinct bars to show comparisons between different categories or groups. Choice B (Categories) is incorrect because both histograms and bar graphs can display data based on categories, but histograms use ranges to group continuous data. Choice C (Labels) is incorrect as both types of graphs can have labels to provide context and information. Choice D (Percentages) is incorrect because percentages can be used in both histograms and bar graphs to show proportions, but they are not a defining feature that distinguishes histograms from bar graphs.
5. Solve for x: 2x - 7 = 3
- A. x = 4
- B. x = 3
- C. x = -2
- D. x = 5
Correct answer: D
Rationale: To solve the equation for x, follow these steps: 2x - 7 = 3. Add 7 to both sides to isolate 2x, resulting in 2x = 10. Then, divide by 2 on both sides to find x, which gives x = 5. Therefore, the correct answer is x = 5. Choices A, B, and C are incorrect because they do not accurately solve the equation.
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