ATI TEAS 7
TEAS 7 science practice questions
1. Which of the following factors would NOT affect the solubility of a solid solute in a liquid solvent?
- A. Temperature
- B. Pressure
- C. Particle size
- D. Nature of the solute and solvent
Correct answer: B
Rationale: Pressure does not typically affect the solubility of a solid solute in a liquid solvent. Solubility is primarily influenced by factors such as temperature, particle size, and the nature of the solute and solvent. Increasing pressure generally has a minimal effect on the solubility of solids in liquids. The impact of pressure on solubility is more significant for gases in liquids rather than solids in liquids. Therefore, option B is the correct answer. Options A, C, and D directly impact the solubility of a solid solute in a liquid solvent. Temperature affects the solubility as it changes the kinetic energy of particles, particle size can impact the surface area available for interaction between solute and solvent, and the nature of the solute and solvent influences their intermolecular interactions and compatibility.
2. Which hormone is responsible for the characteristic changes experienced during puberty, such as breast development and menstruation in females?
- A. Follicle-stimulating hormone (FSH)
- B. Luteinizing hormone (LH)
- C. Estrogen
- D. Progesterone
Correct answer: C
Rationale: Estrogen is the hormone responsible for the characteristic changes experienced during puberty in females, such as breast development and menstruation. Estrogen plays a crucial role in the development of secondary sexual characteristics and the regulation of the menstrual cycle. Follicle-stimulating hormone (FSH) and luteinizing hormone (LH) are primarily involved in the regulation of the menstrual cycle and ovulation. Progesterone, on the other hand, is important for preparing the uterus for pregnancy and maintaining pregnancy, but it is not the primary hormone responsible for the changes seen during puberty in females.
3. What is the stage of mitosis during which the nuclear envelope reforms?
- A. Prophase
- B. Metaphase
- C. Telophase
- D. Cytokinesis
Correct answer: C
Rationale: During telophase, the nuclear envelope reforms around the separated sister chromatids at opposite poles of the cell. This stage marks the reversal of the processes that occurred during prophase, where the nuclear envelope breaks down. Metaphase is characterized by the alignment of chromosomes along the metaphase plate in the cell's center. Cytokinesis is the final step of cell division involving cytoplasmic division to form two daughter cells, but it does not involve the reformation of the nuclear envelope. Therefore, choice C (Telophase) is the correct answer as it specifically involves the reformation of the nuclear envelope, distinguishing it from the other stages of mitosis.
4. Which of the following is a common property of both acids and bases?
- A. React with metals to produce hydrogen gas
- B. Taste sour
- C. Turn blue litmus paper red
- D. Conduct electricity when dissolved in water
Correct answer: D
Rationale: The correct answer is D. Both acids and bases can conduct electricity when dissolved in water. Acids ionize in water to produce H+ ions, which can carry an electric current, while bases ionize to produce OH- ions, which also conduct electricity. The other options are not common properties of both acids and bases. Reacting with metals to produce hydrogen gas is characteristic of acids, tasting sour is a property of acids, and turning blue litmus paper red is a property of bases, not a common property shared by both.
5. Which functional group is commonly found in ketones?
- A. Hydroxyl
- B. Carbonyl
- C. Ester
- D. Amine
Correct answer: B
Rationale: Ketones contain a carbonyl functional group, which consists of a carbon atom double-bonded to an oxygen atom. This distinguishes ketones from other functional groups such as hydroxyl, ester, and amine. The presence of the carbonyl group, not hydroxyl (choice A), ester (choice C), or amine (choice D), is characteristic of ketones, making choice B, 'Carbonyl', the correct answer.
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