Nursing Elites

1. Which muscle is voluntary, striated, and found attached to bones?

• A. Smooth muscle
• B. Skeletal muscle
• C. Cardiac muscle
• D. Epithelial muscle

Correct answer: B

Rationale: The correct answer is B, Skeletal muscle. Skeletal muscle is both voluntary and striated, as well as attached to bones, allowing for movement. Smooth muscle, on the other hand, is involuntary and typically found in the walls of internal organs, controlling functions like digestion. Cardiac muscle is also striated, but it is involuntary and specifically found in the heart, responsible for cardiac contractions to pump blood. 'Epithelial muscle' is an incorrect term; epithelial tissue is a type of tissue that forms the linings of various body surfaces and structures, not a muscle type.

2. What is the primary function of tight junctions, specialized regions between animal cells?

• A. Communication between cells
• B. Anchorage between cells
• C. Selective passage of materials
• D. All of the above

Correct answer: C

Rationale: The correct answer is C: Selective passage of materials. Tight junctions act as specialized structures between animal cells that create a barrier to the passage of materials. Their primary function is to prevent the leakage of extracellular fluid and control the selective passage of molecules between cells. This selective control is crucial in regulating the movement of substances across cell layers. Tight junctions do not directly facilitate communication between cells or provide anchorage between cells, as their main role is to regulate the passage of materials. Choices A and B are incorrect as tight junctions do not primarily serve for communication or anchorage between cells.

3. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

4. The function of synergists can best be described as which of the following? I. They assist primary movers in completing the specific movement II. They stabilize the point of origin and provide extra pull near the insertion III. They help prevent unwanted movement at a joint

• A. I, II
• B. I, III
• C. II, III
• D. All of the above

Correct answer: A

Rationale: Synergists are muscles that assist the primary movers (agonists) in completing specific movements (I). Additionally, they stabilize the point of origin and provide extra pull near the insertion, aiding in movement efficiency (II). While synergists may contribute to stability, their primary role is to assist in movement rather than prevent unwanted movement at a joint; hence, options I and II offer the most accurate descriptions of their function. Choice B is incorrect because synergists do not primarily help prevent unwanted movement at a joint (III). Choice C is incorrect as it combines stabilization of the point of origin and preventing unwanted movement, which is not the primary function of synergists.

5. Which of the following is the antiparticle of a neutron?

• A. Antineutrino
• B. Positron
• C. Antiproton
• D. Electron

Correct answer: C

Rationale: The antiparticle of a neutron is an antineutron, which is composed of an antiproton and an antineutrino. The antineutrino (choice A) is not the antiparticle of a neutron. A positron (choice B) is the antiparticle of an electron, not a neutron. An electron (choice D) is a fundamental particle, not an antiparticle. Therefore, the correct answer is an antiproton (choice C), as it forms an antineutron when combined with an antineutrino.

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