Nursing Elites

1. When rounding 245.2678 to the nearest thousandth, which place value would be used to decide whether to round up or round down?

• A. Ten-thousandths
• B. Thousandths
• C. Hundredths
• D. Thousand

Correct answer: A

Rationale: When rounding a number to the nearest thousandth, you look at the digit in the ten-thousandths place to determine whether to round up or down the digit in the thousandths place. In this case, rounding 245.2678 to the nearest thousandth, the digit in the ten-thousandths place is 6, which is greater than or equal to 5, so you would round up the digit in the thousandths place. Therefore, the correct answer is the ten-thousandths place. Choices B, C, and D are incorrect because they do not directly influence the rounding of the thousandths place in this scenario.

2. A driver drove 305 miles at 65 mph, stopped for 15 minutes, then drove another 162 miles at 80 mph. How long was the trip?

• A. 6.44 hours
• B. 6.69 hours
• C. 6.97 hours
• D. 5.97 hours

Correct answer: B

Rationale: To find the total trip duration, calculate the driving time for each segment and add the stop time. The driving time for the first segment is 305 miles ÷ 65 mph = 4.69 hours. The driving time for the second segment is 162 miles ÷ 80 mph = 2.025 hours. Adding the 15-minute stop (0.25 hours) gives a total time of 4.69 hours + 2.025 hours + 0.25 hours = 6.965 hours, which is closest to 6.69 hours (Choice B). Option A is incorrect as it miscalculates the total duration. Option C is incorrect as it overestimates the total duration. Option D is incorrect as it underestimates the total duration.

3. Solve the inequality for the unknown.

• A. x > 5
• B. x < 5
• C. x >= 5
• D. x <= 5

Correct answer: A

Rationale: When solving an inequality, the direction of the inequality sign changes depending on the operation performed. In this case, if the given inequality simplifies to x > 5, it means that the unknown value x must be greater than 5 for the inequality to hold true. Therefore, x > 5 is the correct solution. Option A is correct. Choices B, C, and D are incorrect because they do not correctly represent the relationship between x and 5 based on the given inequality.

4. The second midwife allocates 1/2 of her funds to pay an office administrator, plus another 1/10 for office supplies. What is the total fraction of the second midwife's budget that is spent on the office administrator and office supplies?

• A. 3/5
• B. 2/12
• C. 2/20
• D. 1/20

Correct answer: A

Rationale: To find the total fraction of the second midwife's budget spent on the office administrator and office supplies, add the fractions. The midwife allocates 1/2 of her funds to the office administrator (1/2) and another 1/10 for office supplies. Adding 1/2 and 1/10 gives a total of 3/5. Choice A (3/5) is correct. Choice B (2/12) is incorrect as it simplifies to 1/6, which is not the total fraction. Choice C (2/20) is incorrect as it simplifies to 1/10, which is only the fraction spent on office supplies, not the total. Choice D (1/20) is incorrect as it represents only the fraction spent on office supplies, not the total spent on both the administrator and supplies.

5. What kind of relationship between a predictor and a dependent variable is indicated by a line that travels from the bottom-left of a graph to the upper-right of the graph?

• A. Positive
• B. Negative
• C. Exponential
• D. Logarithmic

Correct answer: A

Rationale: A line that travels from the bottom-left of a graph to the upper-right of the graph signifies a positive relationship between the predictor and dependent variable. This indicates that as the predictor variable increases, the dependent variable also increases. Choice B, 'Negative,' is incorrect as a negative relationship would be depicted by a line that travels from the top-left to the bottom-right of the graph. Choices C and D, 'Exponential' and 'Logarithmic,' respectively, represent specific types of relationships characterized by non-linear patterns, unlike the linear positive relationship shown in the described scenario.

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