Nursing Elites

1. Solve the system of equations. Equation 1: 2x + y = 0 Equation 2: x - 2y = 8

• A. (1.8, 3.6) and (-1.8, -3.6)
• B. (1.8, -3.6) and (-1.8, 3.6)
• C. (1.3, 2.6) and (-1.3, -2.6)
• D. (-1.3, 2.6) and (1.3, -2.6)

Correct answer: B

Rationale: From Equation 1: 2x + y = 0. Solve for y: y = -2x. Substitute y = -2x into Equation 2: x - 2(-2x) = 8. Simplify to x + 4x = 8, then 5x = 8, and x = 8 ÷ 5 = 1.6. Substitute x = 1.6 back into y = -2x to find y = -3.2. Therefore, one solution is (1.6, -3.2). To find the second solution, use -1.6 for x to get (-1.6, 3.2). Thus, the correct answer is B, representing the solutions (1.8, -3.6) and (-1.8, 3.6). Choices A, C, and D contain incorrect values that do not match the solutions derived from solving the system of equations.

2. Solve for x: 2x + 6 = 14

• A. x = 4
• B. x = 8
• C. x = 10
• D. x = 13

Correct answer: A

Rationale: To solve the equation 2x + 6 = 14, you first subtract 6 from both sides to isolate 2x. This gives 2x = 8. Then, divide by 2 on both sides to find x. Therefore, x = 4. Choices B, C, and D are incorrect as they do not correctly follow the steps of solving the equation.

3. Bernard can make $80 per day. If he needs to make $300 and only works full days, how many days will this take?

• A. 2
• B. 3
• C. 4
• D. 5

Correct answer: C

Rationale: To find out how many days Bernard needs to work to make $300, we divide the total amount he needs by how much he makes per day: $300 / $80 = 3.75 days. Since Bernard can only work full days, he would need to work for 4 days to make $300. Therefore, the correct answer is 4 days. Choice A (2 days) is incorrect because it does not match the calculation based on his daily earnings. Choice B (3 days) is incorrect as the calculated result is not a whole number, so Bernard needs to work for more than 3 days. Choice D (5 days) is incorrect as it exceeds the calculated number of days needed to make $300.

4. How can you distinguish between these three types of graphs - scatterplots: Quadratic, Exponential, Linear?

• A. Linear: straight line; Quadratic: U-shape; Exponential: rises or falls quickly in one direction
• B. Linear: curved line; Quadratic: straight line; Exponential: horizontal line
• C. Linear: zigzag line; Quadratic: U-shape; Exponential: flat line
• D. Linear: straight line; Quadratic: W-shape; Exponential: vertical line

Correct answer: A

Rationale: To differentiate between the three types of graphs - scatterplots, a linear graph will display a straight line, a quadratic graph will have a U-shape, and an exponential graph will show a rapid rise or fall in one direction. Choice B is incorrect because linear graphs are represented by straight lines, not curved lines. Choice C is incorrect as linear graphs do not exhibit zigzag patterns, and exponential graphs do not typically result in flat lines. Choice D is incorrect because quadratic graphs form a U-shape, not a W-shape, and exponential graphs do not represent vertical lines.

5. If Stella's current weight is 56 kilograms, which of the following is her approximate weight in pounds? (Note: 1 kilogram is approximately equal to 2.2 pounds.)

• A. 123 pounds
• B. 110 pounds
• C. 156 pounds
• D. 137 pounds

Correct answer: A

Rationale: To convert Stella's weight from kilograms to pounds, you multiply her weight in kilograms (56) by the conversion factor (2.2): 56 × 2.2 = 123.2 pounds. Since we need to find the approximate weight in pounds, the closest option is 123 pounds, making choice A the correct answer. Choices B, C, and D are incorrect because they do not reflect the accurate conversion of Stella's weight from kilograms to pounds.

Similar Questions