Nursing Elites

1. Simplify the following expression: 13 - 3/22 - 11

• A. 19/22
• B. 7/22
• C. 10/11
• D. 5/11

Correct answer: B

Rationale: To simplify the expression, first find a common denominator for the fractions. 3/22 can be rewritten as 6/22. Now, the expression becomes 13/22 - 6/22 - 11. Subtracting 6/22 from 13/22 gives 7/22. Therefore, the correct answer is 7/22. Choice A, 19/22, is incorrect as the subtraction was not done properly. Choices C and D are incorrect as they are not part of the expression being simplified.

2. What is the range in the number of houses sold per year?

• A. 20
• B. 25
• C. 29
• D. 35

Correct answer: C

Rationale: The range in the number of houses sold per year is calculated by subtracting the minimum number of houses sold from the maximum number of houses sold. In this case, the range is 42 (maximum) - 11 (minimum) = 31, not 29 as stated in the original rationale. Therefore, choice C (29) is incorrect. Choices A (20), B (25), and D (35) are also incorrect as they do not reflect the correct range of houses sold per year, which is 31.

3. A commuter survey counts the people riding in cars on a highway in the morning. Each car contains only one man, only one woman, or both one man and one woman. Out of 25 cars, 13 contain a woman and 20 contain a man. How many contain both a man and a woman?

• A. 4
• B. 7
• C. 8
• D. 13

Correct answer: C

Rationale: Let's denote the number of cars containing only a man as M, only a woman as W, and both a man and a woman as B. Given that there are 25 cars in total, we have: M + W + B = 25 From the information provided, we know that 13 cars contain a woman (W) and 20 cars contain a man (M). Since each car contains either one man, one woman, or both, the cars that contain both a man and a woman (B) are counted once in each of the M and W categories. Therefore, to find out how many cars contain both a man and a woman, we need to subtract the number of cars that contain only a man and only a woman from the total cars. M + B = 20 (as 20 cars contain a man) W + B = 13 (as 13 cars contain a woman) Solving the above two equations simultaneously, we get: M = 12, W = 5, B = 8 Therefore, 8 cars contain both a man and a woman. Hence, the correct answer is 8. Choice A, B, and D are incorrect as they do not reflect the correct calculation based on the information provided.

4. What is the least common denominator of two fractions?

• A. The smallest number that is a multiple of both denominators
• B. The smallest number that both fractions can divide into evenly
• C. The least common multiple of both denominators
• D. The greatest common factor of both denominators

Correct answer: C

Rationale: The least common denominator of two fractions is the least common multiple of both denominators. This is because the least common denominator is the smallest number that both denominators can divide into evenly, ensuring that both fractions can be expressed with a common denominator. Choice A is incorrect as the least common denominator is a multiple of both denominators, not a number that multiplies into both. Choice B is incorrect because the common denominator needs to be a multiple of both denominators, not just a number they can divide into evenly. Choice D is incorrect as the greatest common factor is not used to find the least common denominator, but rather the least common multiple.

5. In the problem 6 + 3 × 2, which operation should be completed first?

• A. Multiplication
• B. Addition
• C. Division
• D. Subtraction

Correct answer: A

Rationale: The correct answer is 'Multiplication.' According to the order of operations (PEMDAS), which stands for Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right), multiplication should be completed first. In the given expression, 3 × 2 should be solved before adding 6 to the result. This means that the multiplication operation should be prioritized over addition. Choices B, C, and D are incorrect because, in the order of operations, multiplication takes precedence over addition, division, and subtraction, respectively.

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