Nursing Elites

1. Robert scores three new clients every eight months. After how many months has he secured 24 new clients?

• A. 64
• B. 58
• C. 52
• D. 66

Correct answer: A

Rationale: To find out the number of months needed to secure 24 new clients, you can set up a proportion: 3 clients / 8 months = 24 clients / x months. Cross multiplying gives you 3x = 24 * 8. Solving for x: 3x = 192, x = 192 / 3, x = 64. Therefore, Robert will secure 24 new clients after 64 months. Choice A is correct. Choice B (58), Choice C (52), and Choice D (66) are incorrect as they do not align with the correct calculation based on the given proportion.

2. A farmer plans to install fencing around a certain field. If each side of the hexagonal field is 320 feet long, and fencing costs $1.75 per foot, how much will the farmer need to spend on fencing material to enclose the perimeter of the field?

• A. $2,240
• B. $2,800
• C. $3,360
• D. $4,480

Correct answer: C

Rationale: To find the perimeter of a hexagonal field with 6 sides, multiply the length of one side (320 feet) by the number of sides (6): 320 x 6 = 1920 feet. The total cost of the fencing material can be calculated by multiplying the perimeter by the cost per foot: 1920 feet x $1.75 = $3360. Therefore, the farmer will need to spend $3,360 on fencing material to enclose the perimeter of the field. Choice A, B, and D are incorrect as they do not accurately calculate the total cost based on the given measurements and cost per foot.

3. A recipe calls for 5.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?

• A. 10.2 mL
• B. 12 mL
• C. 7.43 mL
• D. 27 mL

Correct answer: D

Rationale: To convert the amount of vanilla from teaspoons to milliliters, we multiply the number of teaspoons by the conversion factor of 4.93 mL/teaspoon. 5.5 teaspoons * 4.93 mL/teaspoon = 27.115 mL, which rounds to 27 mL. Therefore, the correct amount of vanilla in mL is 27 mL. Choice A (10.2 mL), Choice B (12 mL), and Choice C (7.43 mL) are incorrect as they do not correctly convert the given amount of teaspoons to milliliters based on the provided conversion factor.

4. Which of the following relationships represents no correlation between two variables?

• A. As a student’s class attendance decreases, the student’s overall grade remains the same
• B. As the number of hours a person exercises decreases, the weight of that person increases
• C. As the number of miles driven increases, the amount of gasoline in the tank decreases
• D. As the amount of water a plant receives increases, the growth rate of the plant increases

Correct answer: A

Rationale: Choice A represents no correlation between two variables as it states that as a student’s class attendance decreases, the student’s overall grade remains the same. This scenario shows no relationship between class attendance and grade. In contrast, choices B, C, and D show clear correlations between the variables mentioned. Choice B indicates a negative correlation between exercise hours and weight gain, choice C indicates a negative correlation between miles driven and gasoline in the tank, and choice D indicates a positive correlation between water intake and plant growth rate, making them all examples of correlated relationships.

5. Which of the following best describes the data set below? 1, 1, 2, 2, 2, 2, 3, 3, 7, 7, 8, 8, 8, 8, 9, 9

• A. Uniform
• B. Right-skewed
• C. Bimodal
• D. Left-skewed

Correct answer: C

Rationale: The correct answer is C: Bimodal. A bimodal distribution has two distinct peaks or modes. In this data set, the numbers 2 and 8 appear more frequently than other numbers, creating two modes (2 and 8). Choices A, B, and D are incorrect. Option A, 'Uniform,' describes a distribution where all values have equal frequency, which is not the case in this data set. Options B and D, 'Right-skewed' and 'Left-skewed,' refer to distributions where the data is skewed towards one side, which is not observed in this dataset. Therefore, the data set is best described as bimodal.

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