Nursing Elites

1. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

2. Half of a circular garden with a radius of 11.5 feet needs weeding. Find the area in square feet that needs weeding. Round to the nearest hundredth. Use 3.14 for π.

• A. 207.64
• B. 415.27
• C. 519.08
• D. 726.73

Correct answer: B

Rationale: The area of a circle is given by the formula A = π × r², where r is the radius. Since only half of the garden needs weeding, we calculate half the area. Using the given value of π (3.14) and a radius of 11.5 feet: A = 0.5 × 3.14 × (11.5)² A = 0.5 × 3.14 × 132.25 A = 0.5 × 415.27 A = 207.64 square feet. Thus, the area that needs weeding is approximately 207.64 square feet, making option B the correct answer. Choice A (207.64) is incorrect as it represents the total area of the circular garden, not just half of it. Choice C (519.08) and Choice D (726.73) are also incorrect as they do not reflect the correct calculation for finding the area of half the circular garden.

3. Three friends are sharing a burger. One friend eats a quarter of the burger. The other two friends equally divide the rest among themselves. What portion of the burger did each of the other two friends receive?

• A. 6-Jan
• B. 4-Jan
• C. 4-Mar
• D. 8-Mar

Correct answer: D

Rationale: After one friend eats a quarter of the burger, 3/4 of the burger remains. Dividing this equally between the other two friends means each receives 3/8 of the whole burger. Therefore, the correct answer is 8-Mar. Choice A (6-Jan), Choice B (4-Jan), and Choice C (4-Mar) are incorrect as they do not accurately represent the portion each of the other two friends receives after one friend consumes a quarter of the burger.

4. Which of the following numbers has the greatest value?

• A. 1.4378
• B. 1.07548
• C. 1.43592
• D. 0.89409

Correct answer: B

Rationale: To determine the number with the greatest value among the options, focus on the digit in the tenths place. In this case, 1.07548 has the highest value as it has the digit 7 in the tenths place. Comparing this to the other numbers, 1.4378, 1.43592, and 0.89409 have 4, 3, and 8 in the tenths place, respectively. Therefore, 1.07548 is the number with the greatest value as it has the highest digit in the tenths place.

5. What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?

• A. 3/12
• B. 3/55
• C. 2/10
• D. 1/3

Correct answer: B

Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.

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