Nursing Elites

1. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

2. A soccer field is rectangular in shape and is 100 meters long and 75 meters wide. The hectare is a metric unit of area often used to measure larger areas. Given that 1 hectare = 10,000 square meters, which of the following represents the soccer field’s area in hectares?

• A. 0.75 hectares
• B. 7.5 hectares
• C. 7,500 hectares
• D. 75,000,000 hectares

Correct answer: A

Rationale: To find the area of the soccer field, multiply its length by its width: 100 meters × 75 meters = 7500 square meters. To convert this to hectares, divide by 10,000 (since 1 hectare = 10,000 square meters), resulting in 0.75 hectares. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not correctly convert the area to hectares. B and C are off by a factor of 10, while D is off by a factor of 10,000.

3. During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?

• A. shifts = 20 + 3 + 1/2
• B. shifts = (20)(3)(1/2)
• C. shifts = (20)(3) + 1/2
• D. shifts = 20 + (3)(1/2)

Correct answer: B

Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.

4. A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

• A. 0.96 hours
• B. 6.44 hours
• C. 6.69 hours
• D. 6.97 hours

Correct answer: D

Rationale: To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours. Therefore, it will have been 6.97 hours since the driver began the trip. Choice A is incorrect as it does not account for the time spent driving the second leg of the trip. Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station. Choice C is incorrect as it misses the time taken for the second leg of the trip.

5. A car dealership’s commercials claim that this year’s models are 20% off the list price, plus they will pay the first 3 monthly payments. If a car is listed for $26,580, and the monthly payments are set at $250, what is the total potential savings?

• A. $1,282
• B. $5,566
• C. $6,066
• D. $20,514

Correct answer: C

Rationale: To calculate the total potential savings: First, find the 20% discount on the list price of $26,580: 0.20 × $26,580 = $5,316. Then, determine the savings over the first 3 months of payments: 3 months × $250/month = $750. Add the discount and the monthly payment savings to get the total potential savings: $5,316 + $750 = $6,066. Therefore, the correct answer is $6,066. Choice A, $1,282, is incorrect because it does not account for the total savings from both the discount and the monthly payments. Choice B, $5,566, is incorrect as it miscalculates the total savings by excluding the savings from the monthly payments. Choice D, $20,514, is incorrect as it does not consider the discount and only focuses on the list price.

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