ATI TEAS 7
TEAS Math Questions
1. If you pull an orange block from a bag of 3 orange, 5 green, and 4 purple blocks, what is the probability of consecutively pulling two more orange blocks without replacement?
- A. 1/12
- B. 3/55
- C. 1/55
- D. 2/33
Correct answer: B
Rationale: To calculate the probability of pulling two more orange blocks consecutively without replacement after the initial orange block is pulled, we need to multiply the probabilities. After the first orange block is pulled, there are 2 orange blocks left out of a total of 11 blocks remaining. So, the probability of pulling a second orange block is 2/11. Therefore, the overall probability is (3/12) * (2/11) = 3/55. Choice A (1/12) is incorrect because it only considers the probability of the first orange block being pulled. Choice C (1/55) is incorrect as it represents the probability of pulling two orange blocks in a row, not the consecutive pulls after the initial pull. Choice D (2/33) is incorrect as it does not reflect the correct calculation for the consecutive pulls of orange blocks.
2. Simplify the following expression: 13 - 3/22 - 11
- A. 19/22
- B. 7/22
- C. 10/11
- D. 5/11
Correct answer: B
Rationale: To simplify the expression, first find a common denominator for the fractions. 3/22 can be rewritten as 6/22. Now, the expression becomes 13/22 - 6/22 - 11. Subtracting 6/22 from 13/22 gives 7/22. Therefore, the correct answer is 7/22. Choice A, 19/22, is incorrect as the subtraction was not done properly. Choices C and D are incorrect as they are not part of the expression being simplified.
3. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?
- A. Histogram
- B. Pie chart
- C. Bar graph
- D. Scatter plot
Correct answer: A
Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.
4. Adam is painting the outside of a 4-walled shed. The shed is 5 feet wide, 4 feet deep, and 7 feet high. Which of the following is the amount of paint Adam will need for the four walls?
- A. 80 ft²
- B. 126 ft²
- C. 140 ft²
- D. 560 ft²
Correct answer: B
Rationale: To find the amount of paint needed for the four walls of the shed, calculate the total area of the four walls. The shed has two pairs of identical walls. The area of one pair of walls is 5 feet (width) x 7 feet (height) + 4 feet (depth) x 7 feet (height) = 35 ft² + 28 ft² = 63 ft². Since there are two pairs of walls, the total area for the four walls is 2 x 63 ft² = 126 ft². Therefore, Adam will need 126 ft² of paint for the four walls. Choice A, 80 ft², is incorrect as it does not account for the total surface area of all four walls. Choice C, 140 ft², is incorrect as it overestimates the area required. Choice D, 560 ft², is incorrect as it significantly overestimates the amount of paint needed for the shed.
5. What is the value of the sum of 0.75 and 0.625?
- A. 0.875
- B. 1.375
- C. 1.625
- D. 0.125
Correct answer: B
Rationale: Adding 0.75 and 0.625 gives: 0.75+0.625=1.375.
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