Nursing Elites

1. If you compare a 1 M solution of NaCl to a 1 M solution of glucose (C6H12O6) in water, which solution would have the higher boiling point?

• A. The NaCl solution
• B. The glucose solution
• C. They would have the same boiling point
• D. It depends on the temperature

Correct answer: A

Rationale: 1. Boiling point elevation: When a solute is added to a solvent, it raises the boiling point of the solution compared to the pure solvent. This phenomenon is known as boiling point elevation. 2. Van't Hoff factor: The extent of boiling point elevation depends on the number of particles the solute dissociates into in the solution. NaCl dissociates into two ions (Na+ and Cl-) in water, while glucose does not dissociate into ions. Therefore, NaCl has a higher Van't Hoff factor than glucose. 3. Colligative properties: Boiling point elevation is a colligative property, meaning it depends on the concentration of the solute particles, not the identity of the solute. Since both NaCl and glucose are 1 M solutions, the NaCl solution will have a higher boiling point due to its higher Van't Hoff factor. 4. Conclusion: The NaCl solution

2. When a biologist describes the physical and visible expression of a genetic trait, which of the following is being referred to?

• A. Phenotype
• B. Allele
• C. Gamete
• D. Genotype

Correct answer: A

Rationale: The correct answer is A: Phenotype. Phenotype specifically refers to the observable physical characteristics resulting from the interaction of an individual's genetic makeup (genotype) with environmental influences. It represents the outward expression of an organism's genetic makeup. Allele, represented by choice B, refers to different forms of a gene and is not the visible expression of a trait. Gamete, represented by choice C, is a reproductive cell and not directly related to the physical expression of traits. Genotype, represented by choice D, refers to the genetic makeup of an organism and is distinct from the observable physical characteristics denoted by phenotype.

3. What is the name of the muscular ring that controls the passage of food from the esophagus to the stomach?

• A. Pyloric sphincter
• B. Cardiac sphincter
• C. Ileocecal valve
• D. Sphincter of Oddi

Correct answer: B

Rationale: The correct answer is the Cardiac sphincter (lower esophageal sphincter). It is situated at the junction of the esophagus and the stomach, controlling the passage of food into the stomach. The cardiac sphincter opens and closes to regulate the flow of food and prevent reflux. The pyloric sphincter, on the other hand, is located between the stomach and the small intestine, not the esophagus and stomach. The ileocecal valve is positioned between the small and large intestines, while the Sphincter of Oddi is found in the duodenum, not between the esophagus and stomach.

4. A scientist wants to measure how far a person can run in 30 minutes. Which of the following units should be used to record this measurement as a small number?

• A. Gigameters
• B. Kilometers
• C. Megameters
• D. Terameters

Correct answer: B

Rationale: Kilometers are commonly used for shorter distances and would provide a small and practical number to measure distance in this context. Gigameters, Megameters, and Terameters are much larger units of measurement and would result in very large numbers, making them impractical for measuring the distance a person can run in 30 minutes. Therefore, the correct choice is Kilometers as it is a suitable unit for measuring such distances within a reasonable range.

5. Which process allows for the movement of large molecules, such as proteins and polysaccharides, across the cell membrane?

• A. Endocytosis
• B. Exocytosis
• C. Active transport
• D. Facilitated diffusion

Correct answer: A

Rationale: Endocytosis is the process by which cells engulf large molecules or particles by wrapping the cell membrane around them to form a vesicle that is brought into the cell. This mechanism facilitates the movement of large molecules like proteins and polysaccharides across the cell membrane. Exocytosis involves the release of large molecules or particles from the cell, opposite to the scenario described in the question. Active transport requires energy to move molecules against their concentration gradient and is not primarily used for transporting proteins and polysaccharides. Facilitated diffusion entails the movement of molecules aided by transport proteins but is not the primary mechanism for transporting large molecules such as proteins and polysaccharides.

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