Nursing Elites

1. Given the double bar graph shown below, which of the following statements is true?

• A. Group A is negatively skewed, while Group B is approximately normal.
• B. Group A is positively skewed, while Group B is approximately normal.
• C. Group A is approximately normal, while Group B is negatively skewed.
• D. Group A is approximately normal, while Group B is positively skewed.

Correct answer: B

Rationale: The correct answer is B. In a double bar graph, Group A is positively skewed, meaning its data is clustered on the left and has a tail extending to the right. On the other hand, Group B displays a normal distribution where the data is evenly distributed around the mean. Choices A, C, and D are incorrect as they inaccurately describe the skewness and distribution of the data in Group A and Group B.

2. Adam is painting the outside of a 4-walled shed. The shed is 5 feet wide, 4 feet deep, and 7 feet high. Which of the following is the amount of paint Adam will need for the four walls?

• A. 80 ft²
• B. 126 ft²
• C. 140 ft²
• D. 560 ft²

Correct answer: B

Rationale: To find the amount of paint needed for the four walls of the shed, calculate the total area of the four walls. The shed has two pairs of identical walls. The area of one pair of walls is 5 feet (width) x 7 feet (height) + 4 feet (depth) x 7 feet (height) = 35 ft² + 28 ft² = 63 ft². Since there are two pairs of walls, the total area for the four walls is 2 x 63 ft² = 126 ft². Therefore, Adam will need 126 ft² of paint for the four walls. Choice A, 80 ft², is incorrect as it does not account for the total surface area of all four walls. Choice C, 140 ft², is incorrect as it overestimates the area required. Choice D, 560 ft², is incorrect as it significantly overestimates the amount of paint needed for the shed.

3. During week 1, Nurse Cameron works 5 shifts. During week 2, she worked twice as many shifts as she did in week 1. In week 3, she added 4 shifts to the number of shifts worked in week 2. Which equation describes the number of shifts Nurse Cameron worked in week 3?

• A. Shifts = (2)(5) + 4
• B. Shifts = (4)(5) + 2
• C. Shifts = 5 + 2 + 4
• D. Shifts = (5)(2)(4)

Correct answer: A

Rationale: During week 1, Nurse Cameron worked 5 shifts. In week 2, she worked twice as many shifts as in week 1, which is 10 shifts. In week 3, she added 4 shifts to the number of shifts worked in week 2. Therefore, the total shifts in week 3 can be calculated as (2)(5) + 4 = 10 + 4 = 14 shifts. Choice A correctly represents this calculation. Choices B, C, and D are incorrect because they do not accurately reflect the given scenario and the steps needed to find the total shifts in week 3.

4. What is 15% of 200?

• A. 30
• B. 20
• C. 25
• D. 40

Correct answer: A

Rationale: To find 15% of 200, you multiply 0.15 by 200, which equals 30. Therefore, the correct answer is A. Choice B (20) is incorrect because it represents 10% of 200. Choice C (25) is incorrect as it does not accurately represent 15% of 200. Choice D (40) is incorrect as it represents 20% of 200.

5. Curtis measured the temperature of water in a flask in his science class. The temperature of the water was 35 °C. He carefully heated the flask so that the temperature of the water increased by about 2 °C every 3 minutes. Approximately how much had the temperature of the water increased after 20 minutes?

• A. 10 °C
• B. 13 °C
• C. 15 °C
• D. 35 °C

Correct answer: B

Rationale: To find the increase in temperature after 20 minutes, calculate how many 3-minute intervals are in 20 minutes (20 ÷ 3 = 6.66, rounding to 7 intervals). Then, multiply the temperature increase per interval (2 °C) by the number of intervals (7 intervals), giving a total increase of 14 °C. Therefore, after 20 minutes, the temperature of the water would have increased by approximately 14 °C. Choice A, 10 °C, is incorrect as it underestimates the total increase. Choice C, 15 °C, is incorrect as it overestimates the total increase. Choice D, 35 °C, is incorrect as it represents the initial temperature of the water, not the increase in temperature.

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