ATI TEAS 7
TEAS 7 science practice
1. Connective tissue provides support and connects other tissues. What is the main component that gives connective tissue its strength?
- A. Collagen fibers
- B. Epithelial cells
- C. Nerve cells
- D. Blood cells
Correct answer: A
Rationale: Collagen fibers are the main component that gives connective tissue its strength. Collagen is a fibrous protein that provides structural support and tensile strength to connective tissues, allowing them to withstand stretching and tension. Epithelial cells, nerve cells, and blood cells are not the main components responsible for the strength of connective tissue. Epithelial cells are specialized for covering and lining surfaces, nerve cells transmit signals, and blood cells are involved in various functions like oxygen transport and immune response, but they do not provide the structural strength typical of collagen fibers in connective tissue.
2. Which of the following is an example of a salt?
- A. Sodium hydroxide (NaOH)
- B. Hydrochloric acid (HCl)
- C. Sodium chloride (NaCl)
- D. Sulfuric acid (H₂SO₄)
Correct answer: C
Rationale: Sodium chloride (NaCl) is an example of a salt. Salts are ionic compounds formed by the reaction of an acid with a base. In this case, sodium chloride is formed by the reaction of sodium hydroxide (a base) with hydrochloric acid (an acid). Sodium hydroxide (NaOH), hydrochloric acid (HCl), and sulfuric acid (H₂SO₄) are not salts because they are not formed by the neutralization reaction of an acid and a base, which is a characteristic of salts.
3. What happens to the frequency of a wave when its wavelength is doubled, assuming the speed remains constant?
- A. Frequency remains the same.
- B. Frequency is halved.
- C. Frequency is doubled.
- D. Frequency information is insufficient to determine.
Correct answer: B
Rationale: When the wavelength of a wave is doubled, and the speed of the wave remains constant, the frequency of the wave is halved. This relationship is governed by the equation speed = frequency x wavelength. Therefore, if the wavelength is doubled while the speed remains constant, the frequency must be halved to maintain a constant speed. Choice A is incorrect because frequency and wavelength are inversely proportional when speed is constant. Choice C is incorrect as doubling the wavelength does not result in a doubled frequency. Choice D is incorrect as the relationship between frequency, wavelength, and speed can be determined using the given information.
4. Where is the abdominopelvic cavity in relation to the thoracic cavity?
- A. Dorsal
- B. Ventral
- C. Superior
- D. Inferior
Correct answer: D
Rationale: The abdominopelvic cavity is located inferior to the thoracic cavity. The thoracic cavity contains organs like the heart and lungs, while the abdominopelvic cavity includes the abdomen and pelvis regions. Therefore, the correct answer is D, as the abdominopelvic cavity is positioned below (inferior to) the thoracic cavity. Choice A (Dorsal) is incorrect as it refers to the backside of the body. Choice B (Ventral) is incorrect as it refers to the front side of the body. Choice C (Superior) is incorrect as it indicates a position above the thoracic cavity, which is not the case.
5. What is the oxidation state of carbon in CH4?
- A. +1
- B. -1
- C. +2
- D. -4
Correct answer: D
Rationale: In CH4 (methane), carbon is bonded to four hydrogen atoms. Hydrogen has an oxidation state of +1. Since the overall charge of CH4 is 0, the oxidation state of carbon must be -4 to balance the charges. Each hydrogen contributes an oxidation state of +1, resulting in a total of +4 from hydrogen atoms. To achieve a total oxidation state of 0 for the molecule, carbon must have an oxidation state of -4 to offset the contribution from hydrogen. Therefore, the correct answer is -4. Choices A, B, and C are incorrect: +1 is the oxidation state of hydrogen, -1 is not the oxidation state of carbon in methane, and +2 is not the correct oxidation state of carbon in CH4.
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