Nursing Elites

1. A teacher asked all the students in the class which days of the week they get up after 8 a.m. Which of the following is the best way to display the frequency for each day of the week?

• A. Histogram
• B. Pie chart
• C. Bar graph
• D. Scatter plot

Correct answer: A

Rationale: A histogram is the best way to display the frequency for each day of the week in this scenario. Histograms are ideal for showing the distribution of numerical data by dividing it into intervals and representing the frequency of each interval with bars. In this case, each day of the week can be represented as a category with the frequency of students getting up after 8 a.m. displayed on the vertical axis. Choice B, a pie chart, would not be suitable for this scenario as it is more appropriate for showing parts of a whole, not frequency distributions. Choice C, a bar graph, could potentially work but is more commonly used to compare different categories rather than displaying frequency distribution data. Choice D, a scatter plot, is used to show the relationship between two variables and is not the best choice for displaying frequency for each day of the week.

2. The cost of renting a bicycle is $3.60 per hour. Which equation shows the best relationship between the total cost (C) and the number of hours (h) rented?

• A. C = 3.60h
• B. C = h + 3.60
• C. C = 3.60h + 10.80
• D. C = 10.80h

Correct answer: A

Rationale: The best relationship is C = 3.60h because the cost increases by $3.60 for each hour of rental. This equation represents a linear relationship where the total cost (C) is directly proportional to the number of hours rented (h). Choice B (C = h + 3.60) is incorrect because it wrongly assumes a fixed additional cost of $3.60 regardless of the number of hours rented. Choice C (C = 3.60h + 10.80) is incorrect as it overestimates the initial cost. Choice D (C = 10.80h) is incorrect as it implies a constant rate of $10.80 per hour, which is not the case.

3. Given the histograms shown below, which of the following statements is true?

• A. Group A is negatively skewed and has a mean less than Group B.
• B. Group A is positively skewed and has a mean greater than Group B.
• C. Group B is negatively skewed and has a mean greater than Group A.
• D. Group B is positively skewed and has a mean less than Group A.

Correct answer: C

Rationale: The correct answer is C. Group B is negatively skewed, indicating more high scores, leading to a higher mean for Group B when compared to Group A. Choice A is incorrect because Group A is not negatively skewed and doesn't have a mean less than Group B. Choice B is incorrect as Group A is not positively skewed and its mean is not greater than Group B. Choice D is also incorrect because Group B having a mean less than Group A contradicts the fact that Group B has a higher mean due to being negatively skewed.

4. What percentage of the staff is certified and available to work in the neonatal unit during the holiday if 35% are on vacation and 20% of the remainder are certified?

• A. 0.07
• B. 0.13
• C. 0.65
• D. 0.8

Correct answer: A

Rationale: After 35% of the staff are on vacation, 65% remain. Since 20% of the remaining staff are certified, you multiply 0.20 by 65% (0.20 * 65% = 0.13 or 13%). Therefore, the correct answer is 0.13 or 13%. Choices C and D are incorrect as they do not represent the correct calculation for the percentage of certified staff available. Choice B is incorrect because it incorrectly states the calculated percentage as 0.13 instead of 0.07.

5. Round 8.067 to the nearest tenth.

• A. 8.1
• B. 8.1
• C. 8
• D. 8.11

Correct answer: A

Rationale: To round 8.067 to the nearest tenth, you look at the digit in the hundredth place, which is 6. Since 6 is equal to or greater than 5, you round up the digit in the tenth place. Therefore, 8.067 rounded to the nearest tenth is 8.1. Choice B (8.1) is incorrect as it duplicates the correct answer. Choice C (8) is incorrect as it does not account for the decimal part. Choice D (8.11) is incorrect as it rounds the number to the nearest hundredth, not the nearest tenth.

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