Nursing Elites

1. Which of the following is NOT a method of sterilization?

• A. Autoclave
• B. UV light
• C. Chemical disinfectants
• D. Boiling water

Correct answer: D

Rationale: A) Autoclave: An autoclave is a method of sterilization that uses high pressure and steam to kill microorganisms, making it an effective way to sterilize equipment and materials.\nB) UV light: UV light is a method of sterilization that damages the DNA of microorganisms, preventing them from reproducing and causing infections.\nC) Chemical disinfectants: Chemical disinfectants are used to kill or inactivate microorganisms on surfaces, but they may not always achieve sterilization, which is the complete destruction of all microorganisms.\nD) Boiling water: Boiling water is a method of disinfection rather than sterilization. While boiling water can kill many microorganisms, it may not be effective against all types of bacteria, viruses, and spores, making it unsuitable for achieving sterilization.\n\nTherefore, the correct answer is D) Boiling water, as it is not a method of sterilization.

2. What is the name for the hard, protective protein that makes up hair and nails?

• A. Collagen
• B. Keratin
• C. Elastin
• D. Fibrin

Correct answer: B

Rationale: Keratin is the correct answer as it is the hard, protective protein that comprises hair and nails. Collagen is a different type of protein found in connective tissues, providing structure and support. Elastin imparts elasticity to tissues, allowing them to stretch and recoil. Fibrin is a protein involved in the blood clotting process and is not related to the structure of hair and nails. Therefore, choices A, C, and D are incorrect in the context of the question.

3. Which of the following is an example of a salt?

• A. Sodium hydroxide (NaOH)
• B. Hydrochloric acid (HCl)
• C. Sodium chloride (NaCl)
• D. Sulfuric acid (H₂SO₄)

Correct answer: C

Rationale: Sodium chloride (NaCl) is an example of a salt. Salts are ionic compounds formed by the reaction of an acid with a base. In this case, sodium chloride is formed by the reaction of sodium hydroxide (a base) with hydrochloric acid (an acid). Sodium hydroxide (NaOH), hydrochloric acid (HCl), and sulfuric acid (H₂SO₄) are not salts because they are not formed by the neutralization reaction of an acid and a base, which is a characteristic of salts.

4. Which condition is characterized by inflammation of the inner lining of the stomach?

• A. Gastroesophageal reflux disease (GERD)
• B. Diverticulitis
• C. Ulcerative colitis
• D. Gastritis

Correct answer: D

Rationale: Gastritis is the correct answer as it is characterized by inflammation of the inner lining of the stomach. This inflammation can be caused by various factors such as excessive alcohol consumption, prolonged use of nonsteroidal anti-inflammatory drugs (NSAIDs), infections, or autoimmune diseases. Symptoms of gastritis may include abdominal pain, nausea, vomiting, and loss of appetite. Gastroesophageal reflux disease (GERD) is incorrect because it involves the backflow of stomach acid into the esophagus, leading to symptoms like heartburn and regurgitation, not inflammation of the stomach lining. Diverticulitis refers to inflammation or infection of small pouches that can form in the walls of the colon, not the stomach. Ulcerative colitis is a type of inflammatory bowel disease characterized by inflammation and ulcers in the colon and rectum, not the stomach lining.

5. How does polarization affect the intensity of light passing through a polarizing filter?

• A. All light passes through regardless of polarization.
• B. Light with the same polarization as the filter passes through, while others are blocked.
• C. Light with higher intensity passes through, while weaker light is blocked.
• D. The intensity is reduced for all light, regardless of polarization.

Correct answer: B

Rationale: A polarizing filter only allows light waves with a specific orientation (polarization) to pass through while blocking light waves with different orientations. Therefore, light with the same polarization as the filter will pass through, while light with different polarizations will be blocked. This results in a reduction in intensity for light passing through the polarizing filter. Choice A is incorrect because a polarizing filter selectively filters light based on its polarization. Choice C is incorrect as the intensity of light passing through is determined by its polarization, not solely its intensity. Choice D is incorrect because a polarizing filter affects light based on its polarization, not uniformly reducing the intensity for all light passing through.

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