ATI TEAS 7
Mometrix TEAS 7 science practice test
1. What is the pH of a solution with a hydrogen ion concentration of (1x10^{-9}) M?
- A. 5
- B. 7
- C. 9
- D. 11
Correct answer: C
Rationale: The pH of a solution can be calculated using the formula: pH = -log[H+]. Given that the hydrogen ion concentration is \(1 \times 10^{-9}\) M, the pH can be calculated as pH = -log(1 x 10^-9) = 9. Therefore, the correct answer is C) 9.
2. What potential consequences can chromosomal nondisjunction have on offspring?
- A. Down syndrome, caused by an extra copy of chromosome 21.
- B. Turner syndrome, characterized by the absence of one X chromosome in females.
- C. Klinefelter syndrome, featuring one or more extra X chromosomes in males.
- D. All of the above.
Correct answer: D
Rationale: - Chromosomal nondisjunction is the failure of homologous chromosomes or sister chromatids to separate properly during cell division, leading to an abnormal number of chromosomes in the resulting cells. - Down syndrome is caused by an extra copy of chromosome 21, resulting from nondisjunction during meiosis. Individuals with Down syndrome have three copies of chromosome 21 instead of the usual two. - Turner syndrome is characterized by the absence of one X chromosome in females, leading to a variety of physical and developmental features. - Klinefelter syndrome features one or more extra X chromosomes in males, typically resulting in infertility and other physical characteristics. Therefore, chromosomal nondisjunction can lead to various genetic disorders such as Down syndrome, Turner syndrome, and Klinefelter syndrome, making option D the correct answer.
3. Which type of cell division is responsible for growth and repair?
- A. Meiosis
- B. Mitosis
- C. Binary fission
- D. Osmosis
Correct answer: B
Rationale: Mitosis is the correct type of cell division responsible for growth and repair. During mitosis, a cell divides to produce two identical daughter cells, contributing to growth and tissue repair in multicellular organisms. Meiosis, on the other hand, is involved in the formation of gametes (sperm and egg cells) for sexual reproduction. Binary fission is a form of asexual reproduction in single-celled organisms, and osmosis is the movement of water molecules across a selectively permeable membrane. Therefore, choices A, C, and D are incorrect as they are not directly related to growth and repair in multicellular organisms.
4. Which type of joint allows for the most movement?
- A. Ball-and-socket joint (shoulder)
- B. Hinge joint (elbow)
- C. Fibrocartilaginous joint (wrists)
- D. Suture joint (skull)
Correct answer: A
Rationale: The correct answer is A: Ball-and-socket joint (shoulder). Ball-and-socket joints, exemplified by the shoulder joint, provide the widest range of movement among joint types. These joints facilitate flexion, extension, abduction, adduction, and rotation, allowing for versatile mobility. In a ball-and-socket joint, the rounded end of one bone fits into the socket of another bone, enabling extensive motion capabilities. Choice B, Hinge joint (elbow), allows movement in one plane, limiting its range compared to ball-and-socket joints. Choice C, Fibrocartilaginous joint (wrists), like the intervertebral discs, is meant for stability rather than extensive movement. Choice D, Suture joint (skull), found in the skull bones, is immovable and provides structural support rather than movement.
5. What is the process of converting ammonia, a byproduct of protein digestion, into a less toxic form?
- A. Deamination
- B. Transamination
- C. Decarboxylation
- D. Hydrolysis
Correct answer: A
Rationale: Deamination is the correct answer. It is the process of removing an amino group from a molecule, like converting ammonia (NH3) into a less toxic form such as urea. Ammonia, a byproduct of protein digestion, must be converted into a less toxic form for excretion. Deamination is a crucial step that mainly occurs in the liver through the urea cycle. Transamination involves transferring an amino group from one molecule to another, not removing it as in deamination. Decarboxylation is the removal of a carboxyl group from a molecule, and hydrolysis is the breakdown of a compound by adding water.
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