Nursing Elites

1. What is the formula to calculate gravitational potential energy near the Earth's surface?

• A. Potential Energy = Mass × Acceleration
• B. Potential Energy = Force × Distance
• C. Potential Energy = Mass × Height × Gravity
• D. Potential Energy = Mass × Acceleration due to gravity × Height

Correct answer: D

Rationale: The correct formula to calculate gravitational potential energy near the Earth's surface is Potential Energy = Mass × Acceleration due to gravity × Height. This formula considers the mass of the object, the specific acceleration due to gravity near the Earth's surface (approximately 9.81 m/s^2), and the vertical distance from the reference point. Choice A is incorrect as it does not include height in the formula. Choice B is incorrect as it involves force instead of acceleration due to gravity. Choice C is incorrect as it multiplies mass, height, and gravity, missing the actual acceleration due to gravity term.

2. When two cars with different masses collide head-on, which car experiences a greater change in momentum?

• A. The car with the larger mass
• B. The car with the smaller mass
• C. Both cars experience the same change in momentum
• D. It depends on the initial velocities of the cars

Correct answer: C

Rationale: In a head-on collision between two cars, the law of conservation of momentum states that the total momentum of the isolated system remains constant before and after the collision. The change in momentum of one car is equal in magnitude but opposite in direction to the change in momentum of the other car. As a result, both cars experience the same change in momentum during the collision. Choice A is incorrect because the change in momentum is the same for both cars due to the conservation of momentum principle. Choice B is incorrect as the smaller mass car does not experience a greater change in momentum. Choice D is incorrect as the initial velocities of the cars do not determine which car experiences a greater change in momentum; it is solely dependent on the masses of the colliding cars.

3. What is the muscular sac that stores urine until it is released from the body known as?

• A. Urethra
• B. Bladder
• C. Ureter
• D. Nephron

Correct answer: B

Rationale: The bladder is the muscular sac that stores urine until it is released from the body. It acts as a reservoir for urine until it is eliminated through the urethra. The urethra is the tube responsible for carrying urine from the bladder to the outside. The ureter transports urine from the kidneys to the bladder. The nephron is the structural and functional unit of the kidney involved in the filtration of blood and urine production. Therefore, the correct answer is the bladder, as it specifically fulfills the function of storing urine before its elimination.

4. Which muscular pouch in the upper left abdomen stores food after swallowing and begins mechanical and chemical digestion?

• A. Esophagus
• B. Stomach
• C. Small intestine
• D. Large intestine

Correct answer: B

Rationale: The correct answer is B: Stomach. The stomach is the muscular pouch in the upper left abdomen that stores food after swallowing and begins mechanical and chemical digestion. It secretes gastric juices containing enzymes and hydrochloric acid to break down food particles. The esophagus is a muscular tube that carries food from the mouth to the stomach, while the small intestine and large intestine are primarily involved in the absorption of nutrients and water, respectively. Therefore, the stomach is the organ responsible for the described functions, making it the correct answer in this context.

5. What is the molarity of a solution made by dissolving 4.0 grams of NaCl into enough water to make 120 mL of solution? The atomic mass of Na is 23.0 g/mol, and Cl is 35.5 g/mol.

• A. 0.34 M
• B. 0.57 M
• C. 0.034 M
• D. 0.057 M

Correct answer: B

Rationale: To find the molarity, first calculate the moles of NaCl. Moles of NaCl = 4.0 g / (23.0 g/mol + 35.5 g/mol) = 0.068 mol. Next, use the formula for molarity: Molarity = moles of solute / liters of solution. Molarity = 0.068 mol / 0.120 L = 0.57 M. Therefore, the molarity of the solution is 0.57 M. Choice A, 0.34 M, is incorrect as it does not match the calculated molarity. Choice C, 0.034 M, is incorrect as it is a decimal point off from the correct molarity. Choice D, 0.057 M, is incorrect as it does not match the calculated molarity of 0.57 M.

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