Nursing Elites

1. How can a diet high in fiber content benefit an individual?

• A. aid in weight loss.
• B. reduce diabetic ketoacidosis.
• C. lower cholesterol.
• D. reduce the need for folate.

Correct answer: C

Rationale: A diet high in fiber content can help lower cholesterol levels by reducing the absorption of cholesterol in the bloodstream. Fiber-rich foods, like grains, apples, potatoes, and beans, can aid in this process. While fiber can aid in weight loss by promoting a feeling of fullness and aiding digestion, it is not primarily for fast weight loss. Fiber does not directly reduce the risk of diabetic ketoacidosis, which is more related to managing blood sugar levels through insulin therapy and dietary control. Folate is a B vitamin that is essential for various bodily functions and is not influenced by fiber intake. Therefore, the correct answer is to lower cholesterol, as fiber plays a significant role in this benefit.

2. Which of the following diseases or conditions is least likely to be associated with an increased potential for bleeding?

• A. metastatic liver cancer
• B. gram-negative septicemia
• C. pernicious anemia
• D. iron-deficiency anemia

Correct answer: C

Rationale: Pernicious anemia is least likely to be associated with an increased potential for bleeding compared to the other conditions listed. Pernicious anemia is a condition resulting from vitamin B12 deficiency due to the absence of intrinsic factor, necessary for B12 absorption. While pernicious anemia can lead to neurological issues, it is not directly linked to an increased risk of bleeding. Metastatic liver cancer can cause liver dysfunction leading to coagulopathy, gram-negative septicemia can result in disseminated intravascular coagulation (DIC), and iron-deficiency anemia can lead to microcytic hypochromic red blood cells, increasing the risk of bleeding. Therefore, pernicious anemia is the least likely to be associated with an increased potential for bleeding out of the options provided.

3. A nurse is caring for a client with an elevated urine osmolarity. The nurse should assess the client for:

• A. fluid volume excess.
• B. hyperkalemia.
• C. hypercalcemia.
• D. fluid volume deficit.

Correct answer: D

Rationale: Elevated urine osmolarity indicates that the urine is concentrated, suggesting the body is trying to conserve water. This commonly occurs in conditions like dehydration or fluid volume deficit. Assessing the client for fluid volume excess, hyperkalemia, or hypercalcemia would not be the priority in this situation. Therefore, the correct answer is to assess the client for fluid volume deficit. Fluid volume excess is characterized by decreased urine osmolarity, while hyperkalemia and hypercalcemia are related to electrolyte imbalances and would not directly cause elevated urine osmolarity.

4. Which medication should the nurse withhold if the client's blood pressure is 88/50?

• A. Rosuvastatin (Crestor)
• B. Enalapril (Vasotec)
• C. Digoxin (Lanoxin)
• D. Clopidogrel (Plavix)

Correct answer: B

Rationale: Enalapril (Vasotec) is the correct answer. It is an angiotensin-converting enzyme (ACE) inhibitor that can further lower blood pressure. Given that the client's blood pressure is already low at 88/50, administering Enalapril could exacerbate hypotension and compromise perfusion to vital organs. Rosuvastatin (Crestor), Digoxin (Lanoxin), and Clopidogrel (Plavix) are not contraindicated in the context of low blood pressure and may be administered safely.

5. What is one characteristic of human immunodeficiency virus (HIV)?

• A. The presence of circulating antibodies that neutralize HIV is evidence of exposure to HIV.
• B. HIV replication occurs intracellularly.
• C. HIV integrates its genetic material into the host cell's DNA.
• D. DNA replication is irrelevant to HIV.

Correct answer: C

Rationale: The correct answer is C. HIV integrates its genetic material into the host cell's DNA. The virus uses the enzyme reverse transcriptase to make a DNA copy of its RNA, which is then inserted into the genetic material of the infected cell. Choice A is incorrect because the presence of antibodies does not indicate immunity to HIV but rather exposure to the virus. Choice B is incorrect as HIV replication occurs intracellularly, inside the host cell. Choice D is irrelevant to the characteristics of HIV.

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