Nursing Elites

1. A client has chronic respiratory acidosis caused by end-stage chronic obstructive pulmonary disease (COPD). Oxygen is delivered at 1 L/min via nasal cannula. The nurse teaches the family that the reason for this is to avoid respiratory depression, based on which of the following explanations?

• A. COPD clients are stimulated to breathe by hypoxia.
• B. COPD clients depend on a low carbon dioxide level.
• C. COPD clients tend to retain hydrogen ions if they are given high doses of oxygen.
• D. COPD clients thrive on a high oxygen level.

Correct answer: A

Rationale: In clients with COPD and chronic respiratory acidosis, they are compensating for low oxygen and high carbon dioxide levels. Hypoxia acts as the main stimulus to breathe in individuals with chronic hypercapnia. When oxygen is administered, it can decrease the respiratory drive by eliminating the hypoxic drive and reducing the stimulus to breathe. Therefore, delivering oxygen at 1 L/min via nasal cannula helps prevent respiratory depression by maintaining the hypoxic drive to breathe. The other options are incorrect: COPD clients do not depend on a low carbon dioxide level as they are chronically hypercapnic, they do not retain hydrogen ions with high oxygen doses, and they do not thrive on a high oxygen level.

2. In Parkinson's disease, a client's difficulty in performing voluntary movements is known as:

• A. Akinesia.
• B. Dyskinesia.
• C. Chorea.
• D. Dystonia.

Correct answer: C.

Rationale: In Parkinson's disease, the client's difficulty in performing voluntary movements is termed dyskinesia. Dyskinesia refers to the impairment of the ability to execute voluntary muscle movements. Akinesia, on the other hand, refers to the absence or lack of voluntary movement. Chorea is characterized by involuntary, rapid, irregular movements. Dystonia involves sustained muscle contractions resulting in abnormal postures or twisting movements. Therefore, dyskinesia is the specific term used for the described difficulty in Parkinson's disease.

3. After an escharotomy of the forearm, what is the priority nursing assessment for the client who has returned to your unit?

• A. Infection
• B. Incision
• C. Pain
• D. Tissue perfusion

Correct answer: D

Rationale: The correct answer is "Tissue perfusion." After an escharotomy, the priority assessment is to ensure adequate tissue perfusion to the affected limb. Escharotomy is performed to relieve circulatory compromise by cutting through the eschar, so monitoring tissue perfusion is crucial to assess the effectiveness of the procedure and prevent complications. Assessing for infection is important but comes after ensuring adequate tissue perfusion. Checking the incision is necessary but assessing tissue perfusion takes precedence. Pain assessment is important but not the priority compared to assessing tissue perfusion to prevent ischemic complications.

4. Which type of hepatitis is transmitted via the fecal-oral route?

• A. Hepatitis A
• B. Hepatitis B
• C. Hepatitis C
• D. Hepatitis D

Correct answer: A

Rationale: Hepatitis A is the correct answer because it is transmitted via the fecal-oral route, often through contaminated food or water. Hepatitis B is transmitted through exposure to infectious blood, semen, and other body fluids, not through the fecal-oral route. Hepatitis C is transmitted through blood-to-blood contact, not via the fecal-oral route. Hepatitis D occurs only in individuals infected with Hepatitis B. Therefore, the correct choice for the type of hepatitis transmitted via the fecal-oral route is Hepatitis A.

5. What is one characteristic of human immunodeficiency virus (HIV)?

• A. The presence of circulating antibodies that neutralize HIV is evidence of exposure to HIV.
• B. HIV replication occurs intracellularly.
• C. HIV integrates its genetic material into the host cell's DNA.
• D. DNA replication is irrelevant to HIV.

Correct answer: C

Rationale: The correct answer is C. HIV integrates its genetic material into the host cell's DNA. The virus uses the enzyme reverse transcriptase to make a DNA copy of its RNA, which is then inserted into the genetic material of the infected cell. Choice A is incorrect because the presence of antibodies does not indicate immunity to HIV but rather exposure to the virus. Choice B is incorrect as HIV replication occurs intracellularly, inside the host cell. Choice D is irrelevant to the characteristics of HIV.

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