HESI RN
HESI Medical Surgical Assignment Exam
1. A patient who is taking trimethoprim-sulfamethoxazole (TMP-SMX) calls to report developing an all-over rash. What action should the nurse instruct the patient to perform?
- A. Increase fluid intake.
- B. Take diphenhydramine.
- C. Stop taking TMP-SMX immediately.
- D. Continue taking the medication.
Correct answer: C
Rationale: When a patient develops an all-over rash while taking trimethoprim-sulfamethoxazole (TMP-SMX), it may indicate a serious drug reaction. In this case, the patient should stop taking the medication immediately and notify their healthcare provider. Increasing fluid intake (Choice A) may be beneficial in some cases but is not the priority when a serious drug reaction is suspected. Taking diphenhydramine (Choice B) may help with itching but does not address the underlying issue of a potential drug reaction. Continuing the medication (Choice D) is not advisable when a serious adverse reaction such as a widespread rash occurs.
2. A client is brought to the emergency department by a neighbor. The client is lethargic and has a fruity odor on the breath. The client’s arterial blood gas (ABG) results are pH 7.25, PCO2 34 mm Hg, PO2 86 mm Hg, HCO3 14 mEq/L. Which of the following acid-base disturbances does the nurse recognize in these results?
- A. Metabolic acidosis
- B. Metabolic alkalosis
- C. Respiratory acidosis
- D. Respiratory alkalosis
Correct answer: A
Rationale: The correct answer is 'Metabolic acidosis.' Metabolic acidosis is characterized by a low pH (<7.35) and a low bicarbonate level (HCO3 <22 mEq/L). In this case, the client's ABG results show a pH of 7.25 and an HCO3 level of 14 mEq/L, indicating metabolic acidosis. The PCO2 of 34 mm Hg is normal, ruling out respiratory acidosis or alkalosis. The PO2 of 86 mm Hg is also within the normal range and is not indicative of a respiratory problem. Therefore, the client is experiencing metabolic acidosis based on the ABG results provided.
3. A client with chronic obstructive pulmonary disease (COPD) presented with shortness of breath. Oxygen therapy was started at 2 liters/minute via nasal cannula. The arterial blood gases (ABGs) after treatment were pH 7.36, PaO2 62, PaCO2 59, and HCO3. Which statement describes the most likely cause of the simultaneous increase in both the PaO2 and the PaCO2?
- A. The hypercapnia resulted from the rapid respirations.
- B. The hypoxic drive was reduced by the oxygen therapy.
- C. The client had a pneumothorax which restricted ventilation.
- D. The client had a pulmonary embolism that reduced perfusion.
Correct answer: B
Rationale: In patients with COPD, oxygen therapy can reduce the hypoxic drive, which is the primary stimulus for breathing in these individuals. By providing supplemental oxygen, the hypoxic drive is diminished, resulting in decreased respiratory effort. As a consequence, the PaO2 may increase due to the supplemental oxygen, but this can lead to a decrease in the respiratory drive and subsequent retention of carbon dioxide, causing an increase in PaCO2 levels. Option A is incorrect because rapid respirations would typically lower PaCO2 levels. Option C is incorrect as a pneumothorax would lead to impaired gas exchange and decreased PaO2 levels without necessarily affecting PaCO2 levels. Option D is incorrect as a pulmonary embolism would typically result in ventilation-perfusion mismatch and decreased PaO2 levels without directly impacting PaCO2 levels.
4. During a paracentesis procedure on a client with abdominal ascites, into which position would the nurse assist the client?
- A. Supine
- B. Upright
- C. Left side-lying
- D. Right side-lying
Correct answer: B
Rationale: During a paracentesis procedure for a client with abdominal ascites, the nurse should assist the client into an upright position. Placing the client upright allows the intestines to float posteriorly, reducing the risk of intestinal laceration during catheter insertion. Choices A, C, and D are incorrect because a supine, left side-lying, or right side-lying position would not provide the same benefit of intestinal mobility and protection during the procedure.
5. In a patient with type 1 diabetes, which of the following is a sign of diabetic ketoacidosis (DKA)?
- A. Polyuria
- B. Bradycardia
- C. Dry skin
- D. Tachycardia
Correct answer: D
Rationale: Tachycardia is a sign of diabetic ketoacidosis (DKA) in a patient with type 1 diabetes. In DKA, the body responds to hyperglycemia and dehydration by increasing heart rate. Polyuria (increased urination) is a symptom of diabetes but not specific to DKA. Bradycardia (slow heart rate) and dry skin are not typical signs of DKA; instead, tachycardia and other signs of volume depletion are more common.
Similar Questions
Access More Features
HESI RN Basic
$69.99/ 30 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access
HESI RN Premium
$149.99/ 90 days
- 5,000 Questions with answers
- All HESI courses Coverage
- 30 days access