Nursing Elites

1. A client with a history of diabetes mellitus is admitted with a blood glucose level of 600 mg/dl and is unresponsive. Which intervention should the nurse implement first?

• A. Administer 50% dextrose IV push.
• B. Administer insulin as prescribed.
• C. Monitor the client's urine output.
• D. Obtain a blood glucose level.

Correct answer: A

Rationale: Administering 50% dextrose IV push is the first priority in treating a blood glucose level of 600 mg/dl in a client who is unresponsive due to hyperglycemia. This intervention is crucial to rapidly raise the client's blood glucose levels and address the emergency situation. Administering insulin (Choice B) would further lower the blood glucose level, worsening the client's condition. Monitoring urine output (Choice C) and obtaining a blood glucose level (Choice D) are important assessments but are secondary to the immediate need to address the high blood glucose levels causing the client's unresponsiveness.

2. A 26-year-old female client is admitted to the hospital for treatment of a simple goiter, and levothyroxine sodium (Synthroid) is prescribed. Which symptoms indicate to the nurse that the prescribed dosage is too high for this client?

• A. Palpitations and shortness of breath
• B. Bradycardia and constipation
• C. Lethargy and lack of appetite
• D. Muscle cramping and dry, flushed skin

Correct answer: A

Rationale: The correct answer is A. An overdose of thyroid preparation generally manifests symptoms of an agitated state such as tremors, palpitations, shortness of breath, tachycardia, increased appetite, agitation, sweating, and diarrhea. Palpitations and shortness of breath are signs of excessive thyroid medication. Choices B, C, and D are incorrect symptoms for a dosage that is too high. Bradycardia and constipation, lethargy and lack of appetite, muscle cramping and dry, flushed skin are more indicative of hypothyroidism or an insufficient dosage of levothyroxine.

3. A client with diabetes mellitus is admitted with a blood glucose level of 600 mg/dl and is unresponsive. Which laboratory value is most concerning?

• A. Serum potassium of 3.0 mEq/L
• B. Serum glucose of 200 mg/dl
• C. Serum pH of 7.30
• D. Serum sodium of 135 mEq/L

Correct answer: C

Rationale: In a client with Hyperosmolar Hyperglycemic State (HHS), a serum pH of 7.30 is the most concerning value as it indicates acidosis, a life-threatening condition that requires immediate intervention. Choices A, B, and D are not the most concerning in this scenario. A low serum potassium level (Choice A) may be expected due to cellular shift in hyperglycemia, a serum glucose level of 200 mg/dl (Choice B) is not as concerning compared to the extremely high initial glucose level, and a serum sodium level of 135 mEq/L (Choice D) is within the normal range and not the immediate priority.

4. A client with a postoperative wound that eviscerated yesterday has an elevated temperature. Which intervention is most important for the nurse to implement?

• A. Initiate contact isolation.
• B. Obtain a wound swab for culture and sensitivity.
• C. Assess temperature every 4 hours.
• D. Use alcohol-based solutions for hand hygiene.

Correct answer: B

Rationale: In this scenario, the most critical intervention is to obtain a wound swab for culture and sensitivity. This will help identify the causative organism present in the wound, enabling healthcare providers to prescribe the appropriate treatment. Initiating contact isolation (Choice A) may be necessary in certain situations but is not the priority in this case where infection is suspected. Assessing the temperature (Choice C) is important for monitoring the client's condition but does not address the underlying cause. Using alcohol-based solutions for hand hygiene (Choice D) is a standard practice for infection control but does not directly address the client's specific condition of a postoperative wound with evisceration and elevated temperature.

5. The nurse is reviewing a client's electrocardiogram and determines the PR interval (PRI) is prolonged. What does this finding indicate?

• A. Initiation of the impulses from a location outside the SA node
• B. Inability of the SA node to initiate an impulse at the normal rate
• C. Increased conduction time from the SA node to the AV junction
• D. Interference with the conduction through one or both ventricles

Correct answer: C

Rationale: When the PR interval is prolonged, it signifies an increased conduction time from the SA node through the AV junction. This finding is characteristic of a first-degree heart block where there is a delay in the electrical conduction at the level of the AV node. Choices A, B, and D are incorrect as they do not accurately reflect the significance of a prolonged PR interval.

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