Nursing Elites

1. What is the drug of choice for herpes simplex virus 1, herpes simplex virus 2, and varicella-zoster virus?

• A. HIV.
• B. HSV 1, HSV 2, and VZV.
• C. CMV
• D. Influenza A viruses.

Correct answer: B

Rationale: Acyclovir (Zovirax) is the drug of choice for herpes simplex virus 1 (HSV-1), herpes simplex virus 2 (HSV-2), and varicella-zoster virus (VZV) infections. It works by inhibiting viral DNA replication. Acyclovir is excreted unchanged in the urine, so caution is needed in renal impairment. Choice A, HIV, is incorrect as acyclovir is not the drug of choice for HIV. Choice C, CMV, is incorrect as acyclovir is not the preferred treatment for cytomegalovirus (CMV) infections. Choice D, Influenza A viruses, is incorrect as acyclovir is not used to treat influenza viruses.

2. A female client complains to the nurse at the health department that she has fatigue, shortness of breath, and lightheadedness. Her history reveals no significant medical problems. She states that she is always on a fad diet without any vitamin supplements. Which tests should the nurse expect the client to have first?

• A. peptic ulcer studies
• B. complete blood count, including hematocrit and hemoglobin
• C. genetic testing
• D. hemoglobin electrophoresis

Correct answer: B

Rationale: The correct answer is to perform a complete blood count, including hematocrit and hemoglobin, as the initial tests to assess the client's symptoms related to fatigue, shortness of breath, and lightheadedness. These symptoms can be indicative of anemia, which can be caused by nutritional deficiencies due to fad dieting without vitamin supplements. Peptic ulcer studies, genetic testing, and hemoglobin electrophoresis are not the most appropriate initial tests for the client's presenting symptoms and history. Peptic ulcer studies are not relevant to the client's symptoms. Genetic testing is not indicated based on the client's presentation and history. Hemoglobin electrophoresis is used to diagnose specific types of anemia and is not the first-line test in this scenario. Further testing decisions should be based on the results of the initial tests, the client's history, and other relevant factors.

3. A client begins a regimen of chemotherapy. Her platelet count falls to 98,000. Which action is least likely to increase the risk of hemorrhage?

• A. Test all excreta for occult blood.
• B. Use a soft toothbrush or foam cleaner for oral hygiene.
• C. Implement reverse isolation.
• D. Avoid IM injections.

Correct answer: C

Rationale: The correct answer is to implement reverse isolation. Reverse isolation is a protective measure used to protect patients from infections, not to affect the risk of hemorrhage. Testing all excreta for occult blood (Choice A) is important to monitor for signs of internal bleeding. Using a soft toothbrush or foam cleaner for oral hygiene (Choice B) is recommended to prevent gum bleeding. Avoiding IM injections (Choice D) is crucial to reduce the risk of bleeding in a client with a low platelet count. Therefore, among the given options, implementing reverse isolation is the least likely to increase the risk of hemorrhage.

4. If your patient is acutely psychotic, which of the following independent nursing interventions would not be appropriate?

• A. Conveying calmness through one-on-one interaction
• B. Recognizing and managing your own feelings to prevent escalation of the patient's anxiety level
• C. Encouraging client participation in group therapy
• D. Listening and identifying causes of their behavior

Correct answer: C

Rationale: When a patient is acutely psychotic, they may not be able to effectively participate in group therapy due to their altered mental state. Group settings can be overwhelming and may exacerbate the patient's symptoms. Choices A, B, and D are appropriate interventions. Choice A is correct as providing calmness through one-on-one interaction can be beneficial in establishing trust and reducing anxiety. Choice B is also important as recognizing and managing the nurse's feelings can prevent further escalation of the patient's symptoms. Choice D is relevant as listening and identifying causes of the patient's behavior can aid in understanding and providing appropriate care tailored to the patient's needs.

5. A client arrives in the emergency department after severely lacerating the left hand with a knife. HR 96, BP 150/88, R36. The client is extremely anxious and crying uncontrollably. Based on this assessment, the nurse anticipates that this client would be in which acid-base imbalance?

• A. Respiratory acidosis
• B. Respiratory alkalosis
• C. Metabolic acidosis
• D. Metabolic alkalosis

Correct answer: B

Rationale: The correct answer is respiratory alkalosis. Hyperventilation due to anxiety, pain, shock, severe infection, fever, or liver failure can lead to respiratory alkalosis. In this scenario, the client is extremely anxious and crying uncontrollably, indicating an increased respiratory rate and CO2 loss. Respiratory acidosis (choice A) is incorrect as it is characterized by an increase in CO2 levels, not a loss. Metabolic acidosis (choice C) involves a decrease in blood pH due to an accumulation of acids or loss of bicarbonate, which is not the case here. Metabolic alkalosis (choice D) results from excess bicarbonate or a loss of acids, not from increased CO2 loss due to hyperventilation.

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